Question

表结构如下：

actions: int(10)
unlock: tinyint(1)
user_id: int(20)
name: varchar(50)

我有这样的疑问：

SELECT SUM(actions) AS "sum_actions", SUM(unlock) AS "sum_unlock", user_id, name 
 FROM mytable AS `Results` WHERE user_id != 0 GROUP BY user_id 
 ORDER BY sum_actions DESC LIMIT 0,300

这会导致#1064 - You have an error in your SQL syntax错误。

当我删除SUM(unlock) AS "sum_unlock"时，查询才有效。所以我认为不可能总结TINYINT。所以我改为COUNT(unlock) as "count_unlock"，但这没有帮助。我不想将“unlock”表更改为INT，因为它只有布尔值。如何计算每个user_id的求和解锁表？

Answer 1

unlock是保留字。试试这个：

SELECT SUM(actions) AS "sum_actions", SUM(`unlock`) AS "sum_unlock", user_id, name 
FROM mytable AS `Results`
WHERE user_id != 0
GROUP BY user_id 
ORDER BY sum_actions DESC
LIMIT 0,300

Here是一个保留字列表。

Answer 2

您可以尝试SUM(CAST(unlock AS INT))进行计数，就好像该列是INT列而不实际将其更改为INT列：

SELECT
    SUM(actions) AS "sum_actions",
    SUM(CAST(unlock AS INT)) AS "sum_unlock",
    user_id,
    name 
FROM
    mytable AS `Results`
WHERE
    user_id != 0
GROUP BY
    user_id,
    name
ORDER BY
    sum_actions DESC
LIMIT 0,300

在MySQL中计算TINYINT值

2 个答案: