我正在处理一个简单的HTML表单,该表单检测是否存在记录(在XML文件中)并填充所有字段或检测到表单不存在,并在提交时创建记录(或修改当前的一个,如果它被修改)
我现在正致力于添加非现有记录和/或修改现有记录。
AJAX调用PHP文件,在PHP文件中我想检查记录是否存在,并相应地执行相应的操作。我希望告知表格的用户(没有双关语)执行了什么操作(即“添加记录”或“修改记录”)。
首先,我现在正在做的所有PHP都返回文本added
。我想看看我是否可以“添加记录”以正确显示在原始HTML文件中。
预期:当我点击Submit
时,我希望“添加记录”或“修改记录”消息显示在表单下,具体取决于PHP文件的返回
错误:现在,当我点击Submit
时,表单会自行重置,将所有参数添加到URL中,并且我不会收到来自AJAX请求的任何消息。< / p>
这是我的代码:
HTML页面:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<script type="text/javaScript">
function checkID(val){
if (val.value.length != 6) //Since student ID's are six digits
return;
//inID = val.value;
//if (inID.length < 6) return;
xhr = new XMLHttpRequest();
xhr.open('GET', 'processor.php?studentID=' + document.forms[0].elements[0].value);
xhr.onreadystatechange = function() {
/**
if (xhr.readystate != 4 || xhr.status != 200){
document.getElementById("status").innerHTML = "<p> Not Done Yet</p>";
}
**/
if (xhr.readyState === 4 && xhr.status === 200){
document.getElementById("status").innerHTML = "";
parse(xhr.responseXML);
}
}
xhr.send();
document.getElementById("status").innerHTML = "<p> Not Done Yet</p>";
}
function parse(xml){
if (xml == null) alert("Null!");
var student = xml.getElementsByTagName('student');
if (student.length == 0) alert("No Student's Found with that ID");
var content = student.item('0');
var name = content.getElementsByTagName('fullname');
name = name.item(0).childNodes[0].nodeValue;
document.forms[0].elements[1].value = name;
var phone = content.getElementsByTagName('phone');
phone = phone.item(0).childNodes[0].nodeValue;
document.forms[0].elements[2].value = phone;
var email = content.getElementsByTagName('email');
email = email.item(0).childNodes[0].nodeValue;
document.forms[0].elements[3].value = email;
}
function addOrModify(curr){
xhr2 = new XHRHttpRequest();
xhr2.open('GET', 'addOrModify.php'); //?studentID=' + document.forms[0].elements[0].value);
xhr2.onreadystatechange = function(){
if (xhr2.readyState === 4 && xhr2.status === 200){
if (xhr.responseText == "added") {document.getElementById("status").innerHTML = "<p>Added the Record</p>"};
}
}
xhr.send();
return false;
}
</script>
<style type="text/css">
#container {
margin: 0 auto;
padding: 30px;
text-align: center;
}
.centerp {
font-size: 150%;
text-align: center;
}
table {
align: center;
}
</style>
<title>Student Profile</title>
</head>
<body>
<p class="centerp"> Student Profiles </p>
<div id="container">
<form>
<table align="center">
<label>
<tr>
<td>Student ID</td>
<td><input type="text" name="studentID" onblur="checkID(this)"> </input></label></td>
</tr>
</label>
<label>
<tr>
<td>Name</td>
<td><input type="text" name="name" id="name"> </input></label></td>
</tr>
</label>
<label>
<tr>
<td>Phone</td>
<td><input type="text" name="phone"> </input></label></td>
</tr>
</label>
<label>
<tr>
<td>Email</td>
<td><input type="text" name="email"> </input></label></td>
</tr>
</label>
<tr>
<td> <input type="submit" onclick="return addOrModify()"> </input></td></tr> </td>
</tr>
<tr>
<td> <div id="status">
</div> </td>
</tr>
</table>
</form>
</div>
</body>
</html>
简单的PHP页面:
<?php
aOm();
function aOm(){
header("Content-type: text/plain; charset=utf-8");
echo "added";
}
?>
答案 0 :(得分:1)
代码中的小错字
function addOrModify(curr){
xhr2 = new XMLHttpRequest(); // xhr2 = new XHRHttpRequest();
xhr2.open('GET', 'addOrModify.php'); //?studentID=' + document.forms[0].elements[0].value);
xhr2.onreadystatechange = function(){
if (xhr2.readyState === 4 && xhr2.status === 200){
if (xhr2.responseText == "added") // if (xhr.responseText == "added")
{document.getElementById("status").innerHTML = "<p>Added the Record</p>"};
}
}
xhr2.send(); //xhr.send();
return false;
}
应该让它运作起来。虽然你的PHP代码没有错误