Question

是否可以编写一个返回所有具有不基于身份密钥的聚簇索引的表的查询？

Answer 1

这个怎么样：

SELECT
    TableName = t.name, 
    ClusteredIndexName = i.name,
    ColumnName = c.Name
FROM
    sys.tables t
INNER JOIN 
    sys.indexes i ON t.object_id = i.object_id
INNER JOIN 
    sys.index_columns ic ON i.index_id = ic.index_id AND i.object_id = ic.object_id
INNER JOIN 
    sys.columns c ON ic.column_id = c.column_id AND ic.object_id = c.object_id
WHERE
    i.index_id = 1  -- clustered index
    AND c.is_identity = 0
    AND EXISTS (SELECT * 
                FROM sys.columns c2 
                WHERE ic.object_id = c2.object_id AND c2.is_identity = 1)

好的，此查询将列出那些具有非标识列的主键，但主键约束中还有第二列 IS 一个IDENTITY列。

Answer 2

SELECT  s.name AS schema_name, o.name AS object_name, i.name AS index_name
FROM    sys.indexes i
JOIN    sys.objects o ON i.object_id = o.object_id
JOIN    sys.schemas s ON o.schema_id = s.schema_id
WHERE   i.type = 1 -- Clustered index
--AND       o.is_ms_shipped = 0 -- Uncomment if you want to see only user objects
AND     NOT EXISTS (
    SELECT  * 
    FROM    sys.index_columns ic INNER JOIN sys.columns c ON c.object_id = ic.object_id AND c.column_id = ic.column_id
    WHERE   ic.object_id = i.object_id AND ic.index_id = i.index_id
    AND     c.is_identity = 1 -- Is identity column
)
ORDER BY schema_name, object_name, index_name;

示例输出（AdventureWorks2008R2）：

schema_name    object_name                 index_name
-------------- --------------------------- --------------------------------------------------------------------
HumanResources Employee                    PK_Employee_BusinessEntityID
HumanResources EmployeeDepartmentHistory   PK_EmployeeDepartmentHistory_BusinessEntityID_StartDate_DepartmentID
HumanResources EmployeePayHistory          PK_EmployeePayHistory_BusinessEntityID_RateChangeDate
Person         BusinessEntityAddress       PK_BusinessEntityAddress_BusinessEntityID_AddressID_AddressTypeID
Person         BusinessEntityContact       PK_BusinessEntityContact_BusinessEntityID_PersonID_ContactTypeID

Answer 3

以下查询将为您提供所有用户表，列，数据类型，如果列是集群索引的一部分，它将在结果索引中返回列的序列/顺序，否则它将返回NULL。

SELECT U.name [OWNER],O.name [TABLE_NAME],C.name [COLUMN_NAME],T.name [DATA_TYPE],C.length [DATA_LENGTH], x.keyno [Primary_Key_order]
FROM syscolumns C
inner  join sysobjects O on O.Id=C.Id and o.xtype='U' -- User Tables
inner join sysusers U on O.Uid=U.UID
inner join systypes T on C.xtype=T.xtype
left outer join (Select O.name [TABLE_NAME] , C.name [COLUMN_NAME], IK.keyno
            from syscolumns C
            inner  join sysobjects O on O.Id=C.Id and O.xtype='U' -- User Tables
            join sysindexkeys IK on O.id=IK.ID  and C.colid=IK.COLID and Indid=1 -- Only Clustered Index
            ) x 
            on x.TABLE_NAME=O.name and X.COLUMN_NAME=C.name
order by U.name

SQL Server查询以查找聚簇索引

3 个答案: