Question

此帖子是我昨天早些时候发布的更新（包含触发器代码）

我正在使用SQL Server 2000.我正在编写一个触发器，当字段为Applicant.AppStatusRowID时执行

表申请人链接到表位置，表公司＆amp;表AppStatus。

我的问题是在查询中创建联接。

当Applicant.AppStatusRowID更新时，我想从Applicant.AppStatusRowID，Applicant.FirstName，Applicant.Lastname，Location.LocNumber，Location.LocationName，Company.CompanyCode，AppStatus.DisplayText

获取值。

联接将是：

Select * from Applicant A 
Inner Join AppStatus ast on ast.RowID = a.AppStatusRowID 
Inner Join Location l on l.RowID = a.LocationRowID 
Inner Join Company c on c.RowID = l.CompanyRowID

将其插入审核表（字段为ApplicantID，LastName，FirstName，Date，Time，Company，Location Number，Location Name，StatusDisposition，User）

触发器查询是：

SET QUOTED_IDENTIFIER OFF 
GO
SET ANSI_NULLS ON 
GO

CREATE TRIGGER tri_UpdateAppDispo ON dbo.Test_App
For Update 
AS

declare @Approwid int
        Declare @triggername sysname
        Set @rowCnt = @@rowcount
        Set @triggername = object_name(@@procid)  

        If @rowCnt = 0
                    RETURN

        If Update(appstatusrowid)
        BEGIN

        -----------------------------------------------------------------------------
                    -- insert a record to the AppDispo table, if AppstatusRowid
                    -- is being Updated
                    -----------------------------------------------------------------------------
                    Insert AppDispo(AppID, LastName, FirstName, [DateTime],Company,Location,LocationName,
                    StatusDispo,[Username])

                                Select d.Rowid,d.LastName, d.FirstName, getDate(),C.CompanyCode,l.locnum,l.locname, ast.Displaytext,
                             SUSER_SNAME()+' '+User  
                                From     deleted d with(nolock) 
                            Inner join Test_App a with (nolock) on a.RowID = d.rowid
                            inner join location l with (nolock) on l.rowid = d.Locationrowid
                                            inner join appstatus ast with (nolock) on ast.rowid = d.appstatusrowid 
                                            inner join company c with (nolock) on c.rowid = l.CompanyRowid
                                            --Inner Join Deleted d ON a.RowID = d.RowID
                                            --Where (a.rowid = @Approwid)
        END
GO

有什么想法吗？

Answer 1

尝试使用此代码

SET QUOTED_IDENTIFIER OFF 
GO
SET ANSI_NULLS ON 
GO

CREATE TRIGGER tri_UpdateAppDispo ON dbo.Test_App
For Update 
AS

declare @Approwid int
    Declare @triggername sysname
    Set @rowCnt = @@rowcount
    Set @triggername = object_name(@@procid)  

    If @rowCnt = 0
                RETURN

    If Update(appstatusrowid)
    BEGIN
    -----------------------------------------------------------------------------
                -- insert a record to the AppDispo table, if AppstatusRowid
                -- is being Updated
                -----------------------------------------------------------------------------
                Insert AppDispo(AppID, LastName, FirstName, [DateTime],Company,Location,LocationName,
                StatusDispo,[Username])
                            Select d.Rowid,d.LastName, d.FirstName, getDate(),C.CompanyCode,l.locnum,l.locname, ast.Displaytext,
                         SUSER_SNAME()+' '+User  
                            From     deleted d with(nolock),location l with (nolock),appstatus ast with (nolock),company c with (nolock)
                            where d.Locationrowid =l.rowid and
                                  d.appstatusrowid = ast.rowid  and
                                  c.rowid = l.CompanyRowid
    END GO

使用此代码，您将获得更新删除的行（old_value）

见到你。

编写复杂的触发器

1 个答案: