为什么services.xml无效?

时间:2013-04-15 12:34:08

标签: web-services tomcat configuration axis2

 <service name="CaseCreate" >
<Description>
    Please Type your service description here
</Description>
<messageReceivers>
    <messageReceiver mep="http://www.w3.org/2004/08/wsdl/in-only" class="org.apache.axis2.rpc.receivers.RPCInOnlyMessageReceiver" />
    <messageReceiver  mep="http://www.w3.org/2004/08/wsdl/in-out"  class="org.apache.axis2.rpc.receivers.RPCMessageReceiver"/>
</messageReceivers>
<parameter name="ServiceClass" locked="false">casecreate.CaseCreate</parameter>

<parameter name="InflowSecurity">
   <action>
     <items>UsernameToken</items>
     <passwordCallbackClass>com.myproject.authentication.PWCBHandler</passwordCallbackClass>
    </action>
</parameter>

<module ref="rampart" />

</service>

上面是我尝试使用的services.xml,但是eclipse告诉我这不是一个有效的sevices.xml文件。当我用name =“InflowSevcurity”删除参数时,Eclipse不会抱怨。有谁知道为什么?

0 个答案:

没有答案
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