Question

我使用doctrine 1.2，这是我的架构：

ProviderProduct:
 columns:
   provider_id: 
     type: integer
     primary: true
   product_id:
     type: integer
     primary: true
   num:
     type: integer
     default: 0
     unsigned: true
Provider: 
 columns:
   name: {type: string(255), notnull: true, notblank: true, unique: true}
 relations:
   Products:
     class: Product
     local: provider_id
     foreign: product_id
     refClass: ProviderProduct
Product:
 columns:
    #a lot of columns
 relations:
   Providers:
     class: Provider
     local: product_id
     foreign: provider_id
     refClass: ProviderProduct

我想要的是获得特定提供商的max num（这是ammount）产品。我试过这个问题：

$query = Doctrine_Query::create()->select('p.*')
                                     ->from('Product p')
                                     ->innerJoin('p.Providers pr')
                                     ->where('pr.name = ?', 'WhiteStore')
                                     ->orderBy('ProviderProduct.num');
$query->fetchOne();

结果sql查询：

SELECT p.* FROM product p 
INNER JOIN provider_product p3 ON (p.id = p3.product_id) 
INNER JOIN provider p2 ON p2.id = p3.provider_id, provider_product p4 
WHERE (p2.name = ?) ORDER BY p4.num

正如你所看到的那样，它不按num字段排序。那么，对我的任务来说什么是正确的dql？

Answer 1

How order doctrine query for many-to-many relationship?

您可以使用以下构造：

$query = Doctrine_Query::create()->select('p.*')
->from('Product p')
->innerJoin('p.Providers pr')
->where('pr.name = ?', 'WhiteStore')
->orderBy('p.Providers.ProviderProduct.num');

Doctrine 1的非原生行为是为多对多关系创建一个不可见的别名。您可以使用此别名来构建正确的顺序。

Answer 2

我认为您还需要关联refClass：

ProviderProduct:
  columns:
    provider_id: 
    type: integer
    primary: true
  product_id:
    type: integer
    primary: true
  num:
    type: integer
    default: 0
    unsigned: true
relations:
  Provider: { foreignAlias: ProviderProduct }
  Product:  { foreignAlias: ProviderProduct }

然后通过reffClass联系获取数字：

$query = Doctrine_Query::create()->select('p.*')
  ->from('Product p')
  ->innerJoin('p.ProviderProduct pp')
  ->innerJoin('pp.Provider pr')
  ->where('pr.name = ?', 'WhiteStore')
  ->orderBy('pp.num DESC') // to get de max first
  ->groupBy('p.id') // if any duplicates
  ->limit(1);

$product = $query->fetchOne();

订单原则如何查询多对多关系？

2 个答案: