Question

我在将json数据分配到java类时遇到问题。请帮助任何人，我的java类就像，

public class ListofGridRecords<T> {
    public int Totalrecords;
    public List<T> GridRecords;//using TraderTransaction class.
}

和TraderTransaction类是，

public class TraderTransaction {

  public Date AddedTime;
  public String TransactId;
  public TransactStatus Status;
  public String OtherPartyAccountNo;
  public Double AmountPaid;
  public Double AmountRecieved;
  public Double ClosingBalance;
  public TransactionTypes TransType;
  public String Narration;

  public TraderTransaction() {
    super();
  }
}

和我的json转换函数看起来像，

JsonObject returndata = JsonObject.parse(responseString);
String operationresult = returndata.get("OperationResult").toString();

if (Result.values()[Integer.parseInt(operationresult)] == Result.Success) {
  Gson gson = new Gson();

  @SuppressWarnings("unchecked")
  ListofGridRecords<TraderTransaction> traderlist = 
        gson.fromJson(returndata.get("ResultData").toString(), ListofGridRecords.class);

  Log.i("LIST DATA:", "" + traderlist);
  for (TraderTransaction trader: traderlist.GridRecords) {
    HashMap<String, String> map = new HashMap<String, String>();
    map.put(TRANS_FIRST_COLUMN, currentformatter.format(trader.AddedTime));
    map.put(TRANS_SECOND_COLUMN, trader.TransactId);
    map.put(TRANS_THIRD_COLUMN, trader.OtherPartyAccountNo);
    map.put(TRANS_FOURTH_COLUMN, trader.AmountPaid.toString());
    map.put(TRANS_FIFTH_COLUMN, trader.AmountRecieved.toString());
    map.put(TRANS_SIXTH_COLUMN, OpenOrClosed.values()[Integer.parseInt(trader.TransType.toString())].toString());
    list.add(map);
  }
}

我收到转化错误（TraderTransaction trader：traderlist.GridRecords）。

我的Json数据看起来像，

{
   "Messages":"RESULTS_RETRIEVAL_SUCCESSFULL",
   "OperationResult":0,
   "ResultData":{
      "GridRecords":[
         {
            "AddedBy":"Distributor-9787457361-Rathinavel",
            "AddedTime":"2013-04-12T16:26:24.0140117",
            "AmountPaid":0.0,
            "AmountRecieved":10000.0,
            "ClosingBalance":10000.0,
            "Narration":null,
            "OtherPartyAccountNo":"0102849015327675",
            "Status":2,
            "TransType":2,
            "TransactId":"TDRF483679051236"
         },
         {
            "AddedBy":"Distributor-9787457361-Rathinavel",
            "AddedTime":"2013-04-12T16:20:54.8681857",
            "AmountPaid":0.0,
            "AmountRecieved":0.0,
            "ClosingBalance":0.0,
            "Narration":null,
            "OtherPartyAccountNo":"0102849015327675",
            "Status":0,
            "TransType":2,
            "TransactId":"TDRF706925413802"
         }
      ],
      "Totalrecords":2
   },
   "UpdateAvailable":"0"
}

Answer 1

为了解析你的JSON，我会使用略有不同的策略。由于您似乎只对解析“ResultData”感兴趣，因此我创建了 wrap 响应的类，与您已经创建的类非常相似，即：

public class Response {
  @SerializedName("ResultData")
  public ResultData resultData;
}

和

public class ResultData {
  @SerializedName("GridRecords")
  public List<GridRecord> gridRecords;
  @SerializedName("Totalrecords")
  public int totalrecords;
}

和

public class GridRecord {
  @SerializedName("AddedTime")
  public String addedTime;
  @SerializedName("TransactId")
  public String transactId;
  //other fields...
}

和其他课程，如有必要......

然后，为了解析您的JSON响应，您只需要执行：

Gson gson = new Gson();
Response data = gson.fromJson(responseString, Response.class);

您将能够访问任何字段，例如：

data.resultData.gridRecords.transactId;

注1 ：如果您对JSON响应的更多字段感兴趣，则只需根据JSON响应向 wrap 类添加更多字段。 ..

注意2 ：我已将addedTime的类型更改为String，而不是Date，因为它会因无法解析的日期而引发异常。无论如何，我通常将Response对象中的类型保留为简单String，然后在我从中检索响应的类中，我在创建对象时执行正确的格式化，例如，当您放置您Map ...

中的值

注释3 ：为了遵循Java命名约定，使用注释@SerializedName对于分离JSON响应中和您的应用中的字段名称很有意义，你的属性没有关注......

注4 ：您不应在班级中使用public属性。建议使用private/protected属性及其通讯员getters和setters ...

Json Data分配给java类

1 个答案: