使用两个或多个动态枚举生成DLL

时间:2013-04-15 07:12:48

标签: c# dynamic enums

我跟着这个Q&答:Dynamic enum in C#并且运行良好,最佳答案包含此msdn article: EnumBuilder Class

的代码

此动态枚举代码生成适用于DLL中的一个枚举。问题是当我尝试添加第二个枚举它不起作用时,我只能从引用的DLL访问第一个枚举“高程”。

如何向DLL中添加两个或多个枚举?

class Example
{
    public static void Main()
    {
        // Get the current application domain for the current thread.
        AppDomain currentDomain = AppDomain.CurrentDomain;

        // Create a dynamic assembly in the current application domain,  
        // and allow it to be executed and saved to disk.
        AssemblyName aName = new AssemblyName("TempAssembly");
        AssemblyBuilder ab = currentDomain.DefineDynamicAssembly(
            aName, AssemblyBuilderAccess.RunAndSave);

        // Define a dynamic module in "TempAssembly" assembly. For a single-
        // module assembly, the module has the same name as the assembly.
        ModuleBuilder mb = ab.DefineDynamicModule(aName.Name, aName.Name + ".dll");

        // Define a public enumeration with the name "Elevation" and an 
        // underlying type of Integer.
        EnumBuilder eb = mb.DefineEnum("Elevation", TypeAttributes.Public, typeof(int));

        // Define two members, "High" and "Low".
        eb.DefineLiteral("Low", 0);
        eb.DefineLiteral("High", 1);

        // Create the type and save the assembly.
        Type finished = eb.CreateType();

        //-------------------------------------
        //HERE IS THE CODE TO CREATE A 2ND ENUM
        //-------------------------------------
        EnumBuilder eb1 = mb.DefineEnum("SecondEnum", TypeAttributes.Public, typeof(int));
        eb1.DefineLiteral("Bad", 0);
        eb1.DefineLiteral("Good", 1);
        Type SecondEnum = eb1.CreateType();

        ab.Save(aName.Name + ".dll");
    }
}

1 个答案:

答案 0 :(得分:1)

在工作中发生了奇怪的事情,因为我可以在家里做。在另一个项目中参考TempAsAsmbly,我可以访问SecondEnum

using ProjectName;
...
private void button1_Click(object sender, EventArgs e)
{
    MessageBox.Show(SecondEnum.Good.ToString());
}

<强>更新

原来我添加了两个值(数字),而不是键和值。

SecondEnum.DefineLiteral("Must Be Alphanumeric", Convert.ToInt32(dr[0].ToString()));

更新2:

确保Enum不以空格开始!!