我想知道如何将图片上传到服务器目录?有人可以教我,因为我也想了解更多关于这件事。这是因为我不熟悉这种编码。我试图将图像上传到数据库,它的工作原理,但图像没有进入服务器。只有文件名插入数据库。请帮帮我 !谢谢
<?php
include("db.php");
$id = $_POST['id'];
$bg = trim($_POST['com_bg']);
$ben = trim($_POST['com_benefit']);
$rem = trim($_POST['com_remark']);
//print_r($_FILES);
//echo "<br><br>";
$name = $_FILES['file']['name'];
$format = substr($name, strpos($name, '.'), strlen($name) - 1);
//if they DID upload a file...
if($_FILES['file']['name'])
{
//Check if the file is JPEG,PNG or GIF image
if(($_FILES["file"]["type"] == "image/jpeg")||($_FILES["file"]["type"] == "image/png")||($_FILES["file"]["type"] == "image/gif"))
{
$newname = dirname(__FILE__).'/upload/'.$name;
//Check if the file with the same name is already exists on the server
if (!file_exists($newname))
{
//move it to where we want it to be
move_uploaded_file($_FILES["file"]["tmp_name"],"upload/" . $_FILES["file"]["name"]);
$sql= "UPDATE company SET com_logo='$name' WHERE com_idx = '$id'";
$result = mysql_query($sql);
}
else
{
header("Location: profile_2.php?note=1");
//echo "Error: File ".$_FILES["file"]["name"]." already exists";
}
}
else
{
header("Location: profile_2.php?note=2");
//echo 'wrong extension ';
}
}
$sql= "UPDATE company SET com_intro='$bg',com_description='',com_benefit='$ben',com_remark='$rem' WHERE com_idx = '$id'";
$result = mysql_query($sql);
header("Location: profile_2.php");
?>
答案 0 :(得分:0)
首先,您应该在php.ini文件中检查这些配置
file_uploads
upload_max_filesize
max_input_time
memory_limit
max_execution_time
post_max_size
其次确保yopu想要上传文件的文件夹必须存在并且应该具有适当的权限
<强>建议强> 避免使用mysql_ *函数学习PDO或mysqli
答案 1 :(得分:0)
试试这个例子
<header>
<?php
function UploadOne($fname)
{
$uploaddir = 'uploadedfiles/';
if (is_uploaded_file($fname['tmp_name']))
{
$filname = basename($fname['name']);
$uploadfile = $uploaddir . basename($fname['name']);
if (move_uploaded_file ($fname['tmp_name'], $uploadfile))
$res = "File " . $filname . " was successfully uploaded and stored.<br>";
else
$res = "Could not move ".$fname['tmp_name']." to ".$uploadfile."<br>";
}
else
$res = "File ".$fname['name']." failed to upload.";
return ($res);
}
?>
</header>
<body>
<?php
if ($_FILES['picture']['name'] != "")
{
$res = UploadOne($_FILES['picture']);
$filname = $_FILES['picture']['name'];
echo ($res);
}
?>
<h1>UPLOADING FILES</h1>
<form name="fupload" enctype="multipart/form-data" action="upfiles.php" method="post">
<input type="file" name="picture" />
<input type="submit" value="Submit" />
</form>
</body>