Question

namespace etc...

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Bundle\TwigBundle\Controller\ExceptionController;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpKernel\HttpKernel;
use Symfony\Component\HttpKernel\Exception\FlattenException;
use Symfony\Component\HttpKernel\Log\DebugLoggerInterface;
use Symfony\Component\HttpFoundation\Response;

class MyExceptionController extends ExceptionController
{
    public function showAction(Request $request, FlattenException $exception, DebugLoggerInterface $logger = null, $format = 'html')
    {


    }
}

在控制器内部不执行任何操作会在...中返回“未捕获的异常'Symfony \ Component \ Routing \ Exception \ ResourceNotFoundException'”错误。不确定这是否正确，或者这是否是另一个问题。我希望它只是做通常的行动。

我只需要这样做，这样就可以像访问domain.com/page一样显示指定的路由。

我试过这个：

   $httpKernel = $this->container->get('kernel');
   $response = $httpKernel->forward('AcmeMyBundle:Default:pageAction');
   $this->setResponse(new Response($response));

...但是得到了这个错误：

Call to a member function get() on a non-object in...

Answer 1

您的代码与我昨天所做的相似。我想获取所有NotFoundHttpException异常并尝试将它们转发到默认控制器。我用这样的异常监听器实现了这个：

<?php

namespace Acme\MyBundle\Listener;

use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;

class NotFoundHttpExceptionListener
{
    protected $container;

    public function setContainer($container)
    {
        $this->container = $container;
    }

    public function onKernelException(GetResponseForExceptionEvent $event)
    {
        $exception = $event->getException();
        if ($exception instanceof NotFoundHttpException) {
            $httpKernel = $this->container->get('http_kernel');

            $response = $httpKernel->forward(
                'AcmeMyBundle:Controller:action',
                array(
                    'uri'  => $_SERVER['REQUEST_URI'],
                )
            );

            $response->headers->set('X-Status-Code', '200');
            $event->setResponse($response);
            $event->stopPropagation();
        }
    }
}

请注意，如果要返回另一个状态代码而不是404，则必须使用X-Status-Code，因为HttpKernel中的handleException方法将使用它来设置最终状态代码并将其从标题部分中删除。

我的services.yml看起来像这样：

notfoundhttp.exception.listener:
  class: Acme\MyBundle\Listener\NotFoundHttpExceptionListener
  calls:
    - [ setContainer, [@service_container] ]
  tags:
    - { name: kernel.event_listener, event: kernel.exception, method: onKernelException }

无法使异常控制器工作 - Symfony2

1 个答案: