Question

您好我正在使用IN运算符进行简单查询。我正在使用以下查询

SELECT CustID  FROM Customer WHERE CustID in (6,34,5,4,3,2,1)

现在显示以下订单

但我希望结果与我在IN条款中传递的序列相同。

Answer 1

SELECT CustID  FROM Customer WHERE CustID in (6,34,5,4,3,2,1)
ORDER BY  CASE WHEN CustId = 34
               THEN 5.5
               ELSE CustId
          END DESC

Answer 2

试试这个查询Ramdas ......

SELECT CustID  FROM Customer WHERE CustID in (6,34,5,4,3,2,1) 
ORDER BY CHARINDEX(','+CAST(CustID as varchar(MAX))+',', ',6,34,5,4,3,2,1,')

Answer 3

标准SQL未在select语句或in子句中指定默认顺序。这些行将以DBMS想要的任何顺序返回。

如果您想强制订单具体，您需要使用order-by子句。

某些SQL 实现可能允许配置它，但不能定期配置任何SQL 实现。最糟糕的情况是，您可以尝试以下方式：

select 1 as x, custid from customer where custid = 6
union all select 2 as x, custid from customer where custid = 34
union all select 3 as x, custid from customer where custid = 5
order by x

但它非常丑陋而且效率不高。

Answer 4

你不能，如果你想要那样，你需要一个像'showorder'这样的新领域，你可以在其上订购你的结果：

SELECT CustID FROM Customer WHERE CustID IN (6,34,5,4,3,2,1) ORDER BY showorder

Answer 5

试试这个 -

DECLARE @id TABLE
(
      i INT IDENTITY(1,1)
    , id INT
)

INSERT INTO @id (id)
VALUES (6),(34),(5),(4),(3),(2),(1)

SELECT c.CustID  
FROM dbo.Customer c
JOIN @id i ON i.id = c.CustID
ORDER BY i.i

Answer 6

使用具有有序值的拆分字符串CTE。因此，您将能够对任何数据集进行排序

DECLARE @test nvarchar(100) = '6,34,5,4,3,2,1';
;WITH cte AS
 (
  SELECT SUBSTRING(@test , 0, CHARINDEX( ',', @test)) AS val ,
         CAST(STUFF (@test + ',' , 1, CHARINDEX( ',', @test), '') AS nvarchar(100 )) AS stval,
         1 AS [level]
  UNION ALL
  SELECT SUBSTRING(stval , 0, CHARINDEX( ',', stval)),
         CAST(STUFF (stval, 1, CHARINDEX(',' , stval ), '' ) AS nvarchar(100 )),
         [level] + 1
  FROM cte
  WHERE stval != ''
  )
  SELECT c2.CustID
  FROM dbo.Customer c2 JOIN cte c ON c2.CustID = c.val
  ORDER BY c.[level]

SQLFiddle上的演示

您也可以在功能中包装CTE

CREATE FUNCTION dbo. SplitStrings_CTE(@List nvarchar( 1000), @Delimiter nvarchar(1 ))
RETURNS TABLE
AS
RETURN
WITH cte AS
 (
  SELECT SUBSTRING(@List , 0 , CHARINDEX (@Delimiter, @List)) AS val ,
         CAST(STUFF (@List + @Delimiter, 1 , CHARINDEX (@Delimiter, @List), '') AS nvarchar (1000)) AS stval, 1 AS [level]
  UNION ALL
  SELECT SUBSTRING(stval , 0 , CHARINDEX (@Delimiter, stval)),
         CAST(STUFF (stval , 1, CHARINDEX( @Delimiter , stval ), '' ) AS nvarchar(1000 )), [level] + 1
  FROM cte
  WHERE stval != ''
  )
  SELECT REPLACE(val , ' ' , '' ) AS val, [level]
  FROM cte

使用函数

的SELECT语句

DECLARE @test nvarchar(100) = '6,34,5,4,3,2,1';
SELECT CustID
FROM dbo.Customer c2 JOIN (SELECT val, [level] FROM dbo.SplitStrings_CTE(@test, ',')
                           ) c ON c2.CustID = c.val
ORDER BY c.[level]

OR

DECLARE @test nvarchar(100) = '6,34,5,4,3,2,1';
SELECT CustID
FROM dbo.Customer c2 CROSS APPLY dbo.SplitStrings_CTE(@test, ',') c                           
WHERE c2.CustID = c.val
ORDER BY c.[level]

SQL查询返回无效序列

6 个答案: