代码＃1

Question

我无法理解JavaScript功能级别范围，作为C#程序员看起来与我联系，我将尝试通过代码解释它：

CODE＃1

//Problem
//if same named variable (as in global scope) is used inside function scope,
//then variable defined inside function will be used,global one will be shadowed
var a = 123;
function func() {
    alert(a); //returns undefined,why not just return 123 ?
    //how come js knew that there is variable 'a' will be defined and used in 
    //this function scope ,js is interpreter based ?
    var a = 1; //a is defined inside function
    alert(a); //returns 1 
}
func();

CODE＃2

//when a variable(inside function) not named as same as the global,
//then it can be used inside function,and global variable is not shadowed
var k = 123;
function func2() {
    alert(k); //returns 123 ,why not 'undefined'
    var c = 1;
    alert(c); //returns 1
}
func2();

所以我的问题是

代码＃1

为什么第一次a为undefined，为什么不回复123？如何来js知道有变量'a'将被定义和使用这个函数范围js是基于解释器的吗？

代码＃2

为什么k未定义？

http://jsfiddle.net/Nu2Vu/

Answer 1

代码＃1

Hoisting导致所有变量声明都被置于范围的顶部，但它将赋值保留在原来的位置。当存在对变量的引用时，JavaScript将首先查看当前作用域，如果找不到该变量，它将继续查找作用域链，直到找到该变量为止。此代码的解释如下：

var a = 123; // global var named a declared, assigned a value
function func() {
  var a; // the declaration of the local var a gets
         // hoisted to the top of the scope, but the
         // assignment is left below, so at the point
         // it is initialized with a value of `undefined`
    alert(a); // looks for a local var named a, finds it but
              // it currently has a value of `undefined`

    a = 1; // now the value is assigned to the local a
    alert(a); // returns 1 
}
func();

代码＃2

由于closure，此代码的行为方式与此类似。闭包的基本定义是JavaScript函数不仅可以访问在自己的作用域中定义的变量，还可以访问其父作用域可用的变量。

var k = 123; // declares and assigns a value to global k
function func2() {
    alert(k); // looks for a local var named k, doesn't find it,
              // looks in its parent scope (the global scope in
              // this case) finds k, returns its value of 123
    var c = 1;
    alert(c); //returns 1
}
func2();

Answer 2

第一个代码与此相同：

var a = 123;
function func() {
    var a; //Undefined!
    alert(a); 
    a = 1; 
    alert(a); 
}

这很好地解释了它： https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Statements/var

麻烦了解javascript函数级别范围

2 个答案:

代码＃1

代码＃2