使用URL编辑重定向？ （删除一些'GET'数据）

Question

现在使用

进行页面重定向

  

标题（“位置：{$ _SERVER ['HTTP_REFERER']}”）;

但页面重定向到的URL类似于：

http://localhost:5110/page.php?1st=2&2nd=140413&3rd=547859

如何删除重定向网址的一部分？ URL应该是：

http://localhost:5110/page.php?1st=2&3rd=547859

如果您对此有其他建议，请告诉我...... 感谢。

Answer 1

$referer = parse_url($_SERVER['HTTP_REFERER']);
parse_str($referer['query'], $query);

unset($query['2nd']); // unset the desired element

$referer['query'] = http_build_query($query);
$url = '';
if (array_key_exists('scheme', $referer)) { $url .= "{$referer['scheme']}://"; }
if (array_key_exists('host', $referer)) { $url .= $referer['host']; }
if (array_key_exists('port', $referer)) { $url .= ":{$referer['port']}"; }
if (array_key_exists('path', $referer)) { $url .= $referer['path']; }
if (array_key_exists('query', $referer)) { $url .= "?{$referer['query']}"; }
if (array_key_exists('fragment', $referer)) { $url .= "#{$referer['fragment']}"; }

header("Location: $url");

Answer 2

$ref = explode("?",$_SERVER['HTTP_REFERER']);
parse_str($ref[1], $qs);
unset($qs['query param to remove']);
$qs = http_build_query($qs);
$ref = $ref[0].'?'.$qs;

Answer 3

试试这个：

$str = 'http://localhost:5110/page.php?1st=2&2nd=140413&3rd=547859';
    echo remove_qs_key($str,"2nd");

    function remove_qs_key($url, $key) {
        $url = preg_replace('/(?:&|(\?))' . $key . '=[^&]*(?(1)&|)?/i', "$1", $url);
        return $url;
    }

结果：http://localhost:5110/page.php?1st=2&3rd=547859

Answer 4

$server = $_SERVER['SERVER_NAME']; //Returns the server name(localhost:5110)
$file = $_SERVER['REQUEST_URI']; //Returns the script name and path(/page.php)
echo $server.$file //Returns localhost:5110/page.php