Question

我还在学习C＃，我需要一些帮助。我有一个包含所有要安排的文件的列表框，我使用DateTimePicker和DateTime。问题是程序只启动第一个选定的项目，而不是其他项目。我如何确定项目的优先级，以便顶部首先启动，继续直到退出并继续第二个文件？该程序是一个改进的WPF应用程序。

Startupinfo =列表框

这是代码：

Dictionary<string, string> startupinfoDict = new Dictionary<string, string>();
private bool startjob() //DateTime checking for DateValue and start's if correct value.
{
    DateTime? start = DateTimePicker1.Value;
    DateTime? end = DateTimePicker2.Value;
    DateTime now = DateTime.Now;

    if (start == null || end == null)
    {
        Xceed.Wpf.Toolkit.MessageBox.Show("one of the pickers is empty");
    }
    else if (now >= start.Value && now <= end.Value)
    {
        if (startupinfo.SelectedItem != null)
        {
            string s = startupinfo.SelectedItem.ToString();

            if (startupinfoDict.ContainsKey(s))
            {
              Process process = Process.Start(startupinfoDict[s]);
                process.WaitForExit();
                while (!process.HasExited)
                    Thread.Sleep(500);
                Xceed.Wpf.Toolkit.MessageBox.Show("It works woho");
    }

        }
        return true;
    }
    return false;
}

Answer 1

尝试替换

if (startupinfo.SelectedItem != null)
{
  string s = startupinfo.SelectedItem.ToString();

  if (startupinfoDict.ContainsKey(s))
  {
    Process process = Process.Start(startupinfoDict[s]);
      process.WaitForExit();
      while (!process.HasExited)
          Thread.Sleep(500);
      Xceed.Wpf.Toolkit.MessageBox.Show("It works woho");
  }
}

有一个循环，如

foreach (var selected in startupinfo.SelectedItems)
{
  string s = selected.ToString();

  if (startupinfoDict.ContainsKey(s))
  {
    Process process = Process.Start(startupinfoDict[s]);
      process.WaitForExit();
      while (!process.HasExited)
          Thread.Sleep(500);
      Xceed.Wpf.Toolkit.MessageBox.Show("It works woho");
  }
}

如何启动Listbox中的所有文件？

1 个答案: