Question

从一个表中选择一系列ID然后放入它们的最佳方法是什么通过事务循环一次处理一条记录更新？

$result = mysql_query('SELECT p_code FROM replenishment ');
$ids = array();

while ($p_code = mysql_fetch_row($result)) {
    $ids[] = $p_code[0];
    foreach($ids as $p_code) {
        mysql_query('SELECT @A:=replenishment.p_code,@B:=replenishment.model
                        from replenishment
                        left join replenishment1 on replenishment1.p_code = replenishment.p_code
                        where replenishment.branch=10
                        and replenishment.p_code=$p_code
                        and replenishment.stock < min

                        and replenishment1.stock > 0

                        group by replenishment.p_code');
        mysql_query('UPDATE replenishment1
                        SET stock = (stock - @B), B5=(b5+@B)  WHERE @A = replenishment1.p_code
                        and replenishment1.stock >= @B');
        $row = mysql_fetch_assoc();
    }
}

Answer 1

开始使用PDO或MySQLi。

通过这种方式，您可以管理您的交易并确保数据安全地进入您的数据库。

<?php
try {
  $dbh = new PDO('odbc:SAMPLE', 'db2inst1', 'ibmdb2', 
      array(PDO::ATTR_PERSISTENT => true));
} catch (Exception $e) {
  die("Unable to connect: " . $e->getMessage());
}

try {  
  $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

  $dbh->beginTransaction();

/* You can put your foreach loop over here or you can also do the entire process for single update. It's your choice */

  $dbh->commit();

} catch (Exception $e) {
  $dbh->rollBack();
  echo "Failed: " . $e->getMessage();
}
?>

它保证在完成之前没有其他人能够看到这些变化。如果出现问题，catch块将回滚自事务启动以来所做的所有更改，然后打印出错误消息。

Mysql Php使用事务和提交一次选择并处理一条记录

1 个答案: