基于标准的分类搜索结果

时间:2013-04-13 13:52:36

标签: php pagination

这是我第一次使用基于标准的搜索和分页来收集。

我希望对搜索查询结果进行分页,并能够根据搜索条件转到搜索结果的下一页和上一页。现在,分页将返回表中的所有记录。我试图在NEXT和PREVIOUS按钮的URL链接中包含一个搜索词,但是当我单击按钮时我仍然会从MySQL表中加载所有记录。仅当我单击“下一步”而不是当前页面时,搜索项(例如gallery.php?cmaterial = $ cmaterial)才会出现在URL中。即使这样,搜索结果也与搜索字词不匹配。

我试图从之前关于这个主题的帖子中学习,但我不确定我是否会出错。

这是我的代码:

<?php

$s=$_GET['s'];

// rows to return
$limit=12;

// check for a search parameter
//if (!isset($var))
//  {
//  echo "<p>We dont seem to have a search parameter!</p>";
//  exit;
//  }

$ctitle = mysql_real_escape_string($_POST['ctitle']);
$csubject = mysql_real_escape_string($_POST['csubject']);
$creference = mysql_real_escape_string($_POST['creference']);
$cat_id = ($_POST['cat_id']);
$cmaterial = mysql_real_escape_string($_POST['cmaterial']);
$ctechnic = mysql_real_escape_string($_POST['ctechnic']);
$cartist = mysql_real_escape_string($_POST['cartist']);
$csource = mysql_real_escape_string($_POST['csource']);
$stolen = mysql_real_escape_string($_POST['stolen']);

$sql = "SELECT * FROM collections WHERE c_id>0 AND `ctitle` LIKE '%".$ctitle."%' AND `csubject` LIKE '%".$csubject."%' AND `creference` LIKE '%".$creference."%' AND `cat_id` LIKE '%".$cat_id."%' AND `cmaterial` LIKE '%".$cmaterial."%' AND `ctechnic` LIKE '%".$ctechnic."%' AND `cartist` LIKE '%".$cartist."%' AND `csource` LIKE '%".$csource."%'  ORDER BY c_id ASC";

$sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql);

 $numresults=mysql_query($sql);
 $numrows=mysql_num_rows($numresults);

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
$sql .= " limit $s,$limit";
  $sql_result = mysql_query($sql) or die("Couldn't execute query");

$count = 1 + $s ;

while ($row = mysql_fetch_assoc($sql_result)) {
    $c_id=$row['c_id'];
?>

..............................................HTML RESULT TABLE ...................................................

<?php
$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&cmaterial=$cmaterial\">&lt;&lt;
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }
echo "</table>";
// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

    echo "&nbsp;<a href=\"$PHP_SELF?s=$news&cmaterial=$cmaterial\">Next 10 &gt;&gt;</a>";
  }

$a = $s + ($limit) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
    echo "<p>Showing results $b to $a of $numrows</p>";

?>

0 个答案:

没有答案