将列表分解为空格字符的另一个列表

Question

我想知道，我怎样才能将其中的空间字符列表中的列表分解为另一个列表？

对于exaple，列表包含以下元素：

['John', 'House', '23 4500', 'grass', '542 3256']

到

['John', 'House', '23', '4500', 'grass', '542', '3256']

Answer 1

>>> L = ['John', 'House', '23 4500', 'grass', '542 3256']
>>> [y for x in L for y in x.split()]
['John', 'House', '23', '4500', 'grass', '542', '3256']

可替换地：

>>> from itertools import chain
>>> list(chain.from_iterable(map(str.split, L)))
['John', 'House', '23', '4500', 'grass', '542', '3256']

Answer 2

另一种方法：

>>> l = ['John', 'House', '23 4500', 'grass', '542 3256'];
>>> m = ' '.join(l).split()
['John', 'House', '23', '4500', 'grass', '542', '3256']