我想从一些HTML中提取多个值,我觉得XPath可能是理想的方法。
我想要做的是循环遍历具有类tr
的每个data
然后在循环中获取我需要的数据route_number
a
via
内的文本<tr class="data"><th class="route_number"><a href="/routes/west-midlands/B001v/?tab=" title="Dudley - Sedgley - Wolverhampton - Tettenhall Wood"><span class="route_number small_curvy">1</span></a></th>
<td class="main_and_via">
<a href="/routes/west-midlands/B001v/?tab=" title="Dudley - Sedgley - Wolverhampton - Tettenhall Wood">Dudley - Sedgley - Wolverhampton - Tettenhall Wood</a>
<span class="via"><strong>via</strong> Dudley Road and Tettenhall Road</span>
</td>
</tr><tr class="data"><th class="route_number"><a href="/routes/west-midlands/B002/?tab=" title="Birmingham City Centre - Sparkbrook - Yardley Wood - Warstock / Maypole"><span class="route_number small_curvy">2</span></a></th>
<td class="main_and_via">
<a href="/routes/west-midlands/B002/?tab=" title="Birmingham City Centre - Sparkbrook - Yardley Wood - Warstock / Maypole">Birmingham City Centre - Sparkbrook - Yardley Wood - Warstock / Maypole</a>
<span class="via"><strong>via</strong> Yardley Wood Road</span>
</td>
</tr>
1}}(也在标题中)和tr
文本。
HTML如下:
route number
循环遍历每个anchor text
,然后对via text
,{{1}}和{{1}}理想进行单独查询,还是可以使用单个XPath查询完成?
答案 0 :(得分:0)
您可以使用XPath的“上下文”支持:
$tr = $xpath->query("//tr[@class='data']");
foreach($tr as $row) {
$route = $tr->query("//td[contains(@class, 'route_number')]", $row);
etc...
}
请注意第二个 - &gt; query()调用中的$row
。它提供了搜索开始的上下文。 xpath不会搜索整个DOM树,而只会搜索$ row指向的特定分支。
这样做可以保证您找到的.route_number
是属于您正在处理的$行的那个,而不是来自树中其他位置的.router_number。
答案 1 :(得分:0)
您可以查询所有那些您希望它们的值如果它们总是存在
:(
(//tr[@class = "data"])
/*[@class="route_number"]//span
|//tr[@class = "data"]/*[@class="main_and_via"]/a
|//tr[@class = "data"]//*[@class="via"]
)/text()
结果:
#0: DOMText (length: 1) "1"
#1: DOMText (length: 50) "Dudley - Sedgley - Wolverhampton - Tettenhall Wood"
#2: DOMText (length: 32) " Dudley Road and Tettenhall Road"
#3: DOMText (length: 1) "2"
#4: DOMText (length: 71) "Birmingham City Centre - Sparkbrook - Yardley Wood - Warstock / Maypole"
#5: DOMText (length: 18) " Yardley Wood Road"