Question

我应该在主视图中管理两个不同的视图;我想在我的视图中检测手指的确切数量，也就是说如果我在“第一个视图”中有四个手指，我想要一个var，我说值为4，如果我在“第二个视图”中有3个手指，我想要另一个我告诉你一个值= 3.我告诉你我的代码不能正常工作。

- (void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{

    UITouch *touch = [[event allTouches] anyObject];
    CGPoint touchLocation = [touch locationInView:self.view];

    NSLog(@"cgpoint:%f,%f", touchLocation.x, touchLocation.y);

    if (CGRectContainsPoint(view1.frame, touchLocation)){

        NSLog(@"TOUCH VIEW 1");
        totalTouch1 = [[event allTouches]count];
        NSLog(@"TOTAL TOUCH 1:%d", totalTouch1); 
    }

    else if (CGRectContainsPoint(view2.frame, touchLocation)){

        NSLog(@"TOUCH VIEW 2");
        totalTouch2 = [[event allTouches]count];
        NSLog(@"TOTAL TOUCH 2:%d", totalTouch2);
     }
 }

如果我开始将手指放在“第一个视图”中，我的代码就可以了，但是例如，如果我将第四个手指放在第二个视图中，我的代码首先输入“if”并说我的手指还没有在第一个视图中。我不明白这个问题。

Answer 1

[[event allTouches] anyObject];只提取其中一个触摸。

你需要迭代所有的触摸：

- (void) touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{

    int touch1 = 0;
    int touch2 = 0;
    NSArray *touches = [[event allTouches] allObjects];
    for( UITouch *touch in touches ) {
        CGPoint touchLocation = [touch locationInView:self.view];

        NSLog(@"cgpoint:%f,%f", touchLocation.x, touchLocation.y);

        if (CGRectContainsPoint(view1.frame, touchLocation)){

            NSLog(@"TOUCH VIEW 1");
            touch1 += 1;
            NSLog(@"TOTAL TOUCH 1:%d", totalTouch1);
        }

        else if (CGRectContainsPoint(view2.frame, touchLocation)){

            NSLog(@"TOUCH VIEW 2");
            touch2 += 1;
            NSLog(@"TOTAL TOUCH 2:%d", totalTouch2);
        }
    }

    NSLog(@"Total touches on view 1: %d", touch1);
    NSLog(@"Total touches on view 2: %d", touch2);
}

两个视图与多点触控

1 个答案: