我有一张表如下:
NAME SCORE
-----------------
willy 1
willy 2
willy 3
zoe 4
zoe 5
zoe 6
这是sample
group by
的聚合功能只允许我获得每个name
的最高分。
我想进行查询以获得每个name
的最高2分,我该怎么办?
我的预期输出是
NAME SCORE
-----------------
willy 2
willy 3
zoe 5
zoe 6
答案 0 :(得分:19)
SELECT *
FROM test s
WHERE
(
SELECT COUNT(*)
FROM test f
WHERE f.name = s.name AND
f.score >= s.score
) <= 2
答案 1 :(得分:11)
在MySQL中,您可以使用用户定义的变量来获取每个组中的行号:
select name, score
from
(
SELECT name,
score,
(@row:=if(@prev=name, @row +1, if(@prev:= name, 1, 1))) rn
FROM test123 t
CROSS JOIN (select @row:=0, @prev:=null) c
order by name, score desc
) src
where rn <= 2
order by name, score;
请参阅Demo
答案 2 :(得分:3)
如果您不介意添加其他列,则可以使用以下代码:
SELECT Name, Score, rank() over(partition by Name, order by Score DESC) as rank
From Table
Having rank < 3;
排名功能为每个分区提供排名,在您的情况下,它是名称
答案 3 :(得分:0)
答案 4 :(得分:0)
您可以这样做:
SET @num :=0, @name :='';
SELECT name, score,
@num := IF( @name= name, @num +1, 1 ) AS row_number,
@name := name AS dummy
FROM test
GROUP BY name, score
HAVING row_number <=2
答案 5 :(得分:0)
SELECT * FROM (
SELECT VD.`cat_id` ,
@cat_count := IF( (@cat_id = VD.`cat_id`), @cat_count + 1, 1 ) AS 'DUMMY1',
@cat_id := VD.`cat_id` AS 'DUMMY2',
@cat_count AS 'CAT_COUNT'
FROM videos VD
INNER JOIN categories CT ON CT.`cat_id` = VD.`cat_id`
,(SELECT @cat_count :=1, @cat_id :=-1) AS CID
ORDER BY VD.`cat_id` ASC ) AS `CAT_DETAILS`
WHERE `CAT_COUNT` < 4
------- STEP FOLLOW ----------
1 . select * from ( 'FILTER_DATA_HERE' ) WHERE 'COLUMN_COUNT_CONDITION_HERE'
2. 'FILTER_DATA_HERE'
1. pass 2 variable @cat_count=1 and @cat_id = -1
2. If (@cat_id "match" column_cat_id value)
Then @cat_count = @cat_count + 1
ELSE @cat_count = 1
3. SET @cat_id = column_cat_id
3. 'COLUMN_COUNT_CONDITION_HERE'
1. count_column < count_number
4. ' EXTRA THING '
1. If you want to execute more than one statement inside " if stmt "
2. IF(condition, stmt1 , stmt2 )
1. stmt1 :- CONCAT(exp1, exp2, exp3)
2. stmt2 :- CONCAT(exp1, exp2, exp3)
3. Final "If" Stmt LIKE
1. IF ( condition , CONCAT(exp1, exp2, exp3) , CONCAT(exp1, exp2, exp3) )
答案 6 :(得分:0)
insert into test values('willy',1)
insert into test values('willy',2)
insert into test values('willy',3)
insert into test values('zoe',4)
insert into test values('zoe',5)
insert into test values('zoe',6)
;with temp_cte
as (
select Name, Score,
ROW_NUMBER() OVER (
PARTITION BY Name
ORDER BY Score desc
) row_num
from test
)
select * from temp_cte
where row_num < 3
答案 7 :(得分:-1)
使用此查询。
select * from fruits
where type = 'orange'
order by price limit 2
解决方案:
https://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/