如何使用java压缩文件夹本身

时间：2013-04-12 10:22:21

标签： java zip directory

假设我有以下目录结构。 

D:\reports\january\

一月份内有两个excel文件说A.xls和B.xls。有许多地方已经写过如何使用java.util.zip压缩文件。但是我想在报告文件夹中压缩january文件夹本身，以便在报告中显示 1月和 january.zip 。 （ 这意味着当我解压缩january.zip文件时，我应该获得january文件夹 ）。

任何人都可以使用java.util.zip向我提供执行此操作的代码。请告诉我是否可以通过使用其他库来更轻松地完成此操作。

非常感谢...

16 个答案:

答案 0 :(得分：83)

你试过Zeroturnaround Zip库吗？它真的很整洁！ Zip文件夹只是一个内容：

ZipUtil.pack(new File("D:\\reports\\january\\"), new File("D:\\reports\\january.zip"));

（感谢Oleg Šelajev示例）

答案 1 :(得分：64)

以下是Java 8+示例：

public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
    Path p = Files.createFile(Paths.get(zipFilePath));
    try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p))) {
        Path pp = Paths.get(sourceDirPath);
        Files.walk(pp)
          .filter(path -> !Files.isDirectory(path))
          .forEach(path -> {
              ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
              try {
                  zs.putNextEntry(zipEntry);
                  Files.copy(path, zs);
                  zs.closeEntry();
            } catch (IOException e) {
                System.err.println(e);
            }
          });
    }
}

答案 2 :(得分：49)

可以通过包 java.util.Zip 轻松解决，无需任何额外的Jar个文件

只需使用run it

复制以下代码和IDE即可 
//Import all needed packages
package general;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipUtils {

    private List <String> fileList;
    private static final String OUTPUT_ZIP_FILE = "Folder.zip";
    private static final String SOURCE_FOLDER = "D:\\Reports"; // SourceFolder path

    public ZipUtils() {
        fileList = new ArrayList < String > ();
    }

    public static void main(String[] args) {
        ZipUtils appZip = new ZipUtils();
        appZip.generateFileList(new File(SOURCE_FOLDER));
        appZip.zipIt(OUTPUT_ZIP_FILE);
    }

    public void zipIt(String zipFile) {
        byte[] buffer = new byte[1024];
        String source = new File(SOURCE_FOLDER).getName();
        FileOutputStream fos = null;
        ZipOutputStream zos = null;
        try {
            fos = new FileOutputStream(zipFile);
            zos = new ZipOutputStream(fos);

            System.out.println("Output to Zip : " + zipFile);
            FileInputStream in = null;

            for (String file: this.fileList) {
                System.out.println("File Added : " + file);
                ZipEntry ze = new ZipEntry(source + File.separator + file);
                zos.putNextEntry(ze);
                try {
                    in = new FileInputStream(SOURCE_FOLDER + File.separator + file);
                    int len;
                    while ((len = in .read(buffer)) > 0) {
                        zos.write(buffer, 0, len);
                    }
                } finally {
                    in.close();
                }
            }

            zos.closeEntry();
            System.out.println("Folder successfully compressed");

        } catch (IOException ex) {
            ex.printStackTrace();
        } finally {
            try {
                zos.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }

    public void generateFileList(File node) {
        // add file only
        if (node.isFile()) {
            fileList.add(generateZipEntry(node.toString()));
        }

        if (node.isDirectory()) {
            String[] subNote = node.list();
            for (String filename: subNote) {
                generateFileList(new File(node, filename));
            }
        }
    }

    private String generateZipEntry(String file) {
        return file.substring(SOURCE_FOLDER.length() + 1, file.length());
    }
}

参考mkyong ..我更改了当前问题要求的代码

答案 3 :(得分：32)

这是一个非常简洁的Java 7+解决方案，完全依赖于vanilla JDK类，不需要第三方库：

public static void pack(final Path folder, final Path zipFilePath) throws IOException {
    try (
            FileOutputStream fos = new FileOutputStream(zipFilePath.toFile());
            ZipOutputStream zos = new ZipOutputStream(fos)
    ) {
        Files.walkFileTree(folder, new SimpleFileVisitor<Path>() {
            public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
                zos.putNextEntry(new ZipEntry(folder.relativize(file).toString()));
                Files.copy(file, zos);
                zos.closeEntry();
                return FileVisitResult.CONTINUE;
            }

            public FileVisitResult preVisitDirectory(Path dir, BasicFileAttributes attrs) throws IOException {
                zos.putNextEntry(new ZipEntry(folder.relativize(dir).toString() + "/"));
                zos.closeEntry();
                return FileVisitResult.CONTINUE;
            }
        });
    }
}

它会复制folder中的所有文件，包括空目录，并在zipFilePath创建一个zip存档。

答案 4 :(得分：11)

Java 7 +，commons.io 

public final class ZipUtils {

    public static void zipFolder(final File folder, final File zipFile) throws IOException {
        zipFolder(folder, new FileOutputStream(zipFile));
    }

    public static void zipFolder(final File folder, final OutputStream outputStream) throws IOException {
        try (ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream)) {
            processFolder(folder, zipOutputStream, folder.getPath().length() + 1);
        }
    }

    private static void processFolder(final File folder, final ZipOutputStream zipOutputStream, final int prefixLength)
            throws IOException {
        for (final File file : folder.listFiles()) {
            if (file.isFile()) {
                final ZipEntry zipEntry = new ZipEntry(file.getPath().substring(prefixLength));
                zipOutputStream.putNextEntry(zipEntry);
                try (FileInputStream inputStream = new FileInputStream(file)) {
                    IOUtils.copy(inputStream, zipOutputStream);
                }
                zipOutputStream.closeEntry();
            } else if (file.isDirectory()) {
                processFolder(file, zipOutputStream, prefixLength);
            }
        }
    }
}

答案 5 :(得分：7)

我通常使用曾为此任务编写过的辅助类：

import java.util.zip.*;
import java.io.*;

public class ZipExample {
    public static void main(String[] args){
        ZipHelper zippy = new ZipHelper();
        try {
            zippy.zipDir("folderName","test.zip");
        } catch(IOException e2) {
            System.err.println(e2);
        }
    }
}

class ZipHelper  
{
    public void zipDir(String dirName, String nameZipFile) throws IOException {
        ZipOutputStream zip = null;
        FileOutputStream fW = null;
        fW = new FileOutputStream(nameZipFile);
        zip = new ZipOutputStream(fW);
        addFolderToZip("", dirName, zip);
        zip.close();
        fW.close();
    }

    private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws IOException {
        File folder = new File(srcFolder);
        if (folder.list().length == 0) {
            addFileToZip(path , srcFolder, zip, true);
        }
        else {
            for (String fileName : folder.list()) {
                if (path.equals("")) {
                    addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip, false);
                } 
                else {
                     addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip, false);
                }
            }
        }
    }

    private void addFileToZip(String path, String srcFile, ZipOutputStream zip, boolean flag) throws IOException {
        File folder = new File(srcFile);
        if (flag) {
            zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
        }
        else {
            if (folder.isDirectory()) {
                addFolderToZip(path, srcFile, zip);
            }
            else {
                byte[] buf = new byte[1024];
                int len;
                FileInputStream in = new FileInputStream(srcFile);
                zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
                while ((len = in.read(buf)) > 0) {
                    zip.write(buf, 0, len);
                }
            }
        }
    }
}

答案 6 :(得分：5)

增强的Java 8+示例（从Nikita Koksharov's answer派生）

public static void pack(String sourceDirPath, String zipFilePath) throws IOException {
    Path p = Files.createFile(Paths.get(zipFilePath));
    Path pp = Paths.get(sourceDirPath);
    try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(p));
        Stream<Path> paths = Files.walk(pp)) {
        paths
          .filter(path -> !Files.isDirectory(path))
          .forEach(path -> {
              ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
              try {
                  zs.putNextEntry(zipEntry);
                  Files.copy(path, zs);
                  zs.closeEntry();
            } catch (IOException e) {
                System.err.println(e);
            }
          });
    }
}

Files.walk已包装在try with resources块中，以便可以关闭流。这解决了由SonarQube标识的阻止程序问题。 感谢@Matt Harrison指出这一点。

答案 7 :(得分：4)

我会使用Apache Ant，它有一个API来从Java代码而不是从XML构建文件调用任务。

Project p = new Project();
p.init();
Zip zip = new Zip();
zip.setProject(p);
zip.setDestFile(zipFile); // a java.io.File for the zip you want to create
zip.setBasedir(new File("D:\\reports"));
zip.setIncludes("january/**");
zip.perform();

这里我告诉它从基目录D:\reports开始并压缩january文件夹及其中的所有内容。生成的zip文件中的路径将与相对于D:\reports的原始路径相同，因此它们将包含january前缀。

答案 8 :(得分：2)

试试这个：

 import java.io.File;

 import java.io.FileInputStream;

 import java.io.FileOutputStream;

 import java.util.zip.ZipEntry;

 import java.util.zip.ZipOutputStream;


  public class Zip {

public static void main(String[] a) throws Exception {

    zipFolder("D:\\reports\\january", "D:\\reports\\january.zip");

  }

  static public void zipFolder(String srcFolder, String destZipFile) throws Exception {
    ZipOutputStream zip = null;
    FileOutputStream fileWriter = null;
    fileWriter = new FileOutputStream(destZipFile);
    zip = new ZipOutputStream(fileWriter);
    addFolderToZip("", srcFolder, zip);
    zip.flush();
    zip.close();
  }
  static private void addFileToZip(String path, String srcFile, ZipOutputStream zip)
      throws Exception {
    File folder = new File(srcFile);
    if (folder.isDirectory()) {
      addFolderToZip(path, srcFile, zip);
    } else {
      byte[] buf = new byte[1024];
      int len;
      FileInputStream in = new FileInputStream(srcFile);
      zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
      while ((len = in.read(buf)) > 0) {
        zip.write(buf, 0, len);
      }
    }
  }

  static private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip)
      throws Exception {
    File folder = new File(srcFolder);

    for (String fileName : folder.list()) {
      if (path.equals("")) {
        addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip);
      } else {
        addFileToZip(path + "/" + folder.getName(), srcFolder + "/" +   fileName, zip);
      }
    }
  }



   }

答案 9 :(得分：1)

Java 6 + 

import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class Zip {

    private static final FileFilter FOLDER_FILTER = new FileFilter() {
        @Override
        public boolean accept(File pathname) {
            return pathname.isDirectory();
        }
    };

    private static final FileFilter FILE_FILTER = new FileFilter() {
        @Override
        public boolean accept(File pathname) {
            return pathname.isFile();
        }
    };


    private static void compress(File file, ZipOutputStream outputStream, String path) throws IOException {

        if (file.isDirectory()) {
            File[] subFiles = file.listFiles(FILE_FILTER);
            if (subFiles != null) {
                for (File subFile : subFiles) {
                    compress(subFile, outputStream, new File(path, subFile.getName()).getAbsolutePath());
                }
            }
            File[] subDirs = file.listFiles(FOLDER_FILTER);
            if (subDirs != null) {
                for (File subDir : subDirs) {
                    compress(subDir, outputStream, new File(path, subDir.getName()).getAbsolutePath());
                }
            }
        } else if (file.exists()) {
            outputStream.putNextEntry(new ZipEntry(path));
            FileInputStream inputStream = new FileInputStream(file);
            byte[] buffer = new byte[1024];
            int len;
            while ((len = inputStream.read(buffer)) >= 0) {
                outputStream.write(buffer, 0, len);
            }
            outputStream.closeEntry();
        }
    }

    public static void compress(String dirPath, String zipFilePath) throws IOException {
        File file = new File(dirPath);
        final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFilePath));
        compress(file, outputStream, "/");
        outputStream.close();
    }

}

答案 10 :(得分：1)

我发现这个解决方案对我来说非常好。不需要任何第三方apis

＆＃39;测试＆＃39;实际上是一个文件夹里面会有很多文件。

String folderPath= "C:\Users\Desktop\test";
String zipPath = "C:\Users\Desktop\test1.zip";

private boolean zipDirectory(String folderPath, String zipPath) throws IOException{

        byte[] buffer = new byte[1024];
        FileInputStream fis = null;
        ZipOutputStream zos = null;

        try{
            zos = new ZipOutputStream(new FileOutputStream(zipPath));
            updateSourceFolder(new File(folderPath));

            if (sourceFolder == null) {
                zos.close();
                return false;
            }
            generateFileAndFolderList(new File(folderPath));

            for (String unzippedFile: fileList) {
                System.out.println(sourceFolder + unzippedFile);

                ZipEntry entry = new ZipEntry(unzippedFile);
                zos.putNextEntry(entry);

                if ((unzippedFile.substring(unzippedFile.length()-1)).equals(File.separator))
                    continue;
                try{
                    fis = new FileInputStream(sourceFolder + unzippedFile);
                    int len=0;
                    while ((len = fis.read(buffer))>0) {
                        zos.write(buffer,0,len);
                    }
                } catch(IOException e) {
                    return false;
                } finally {
                    if (fis != null)
                        fis.close();
                }
            }
            zos.closeEntry();
        } catch(IOException e) {
            return false;
        } finally {
            zos.close();
            fileList = null;
            sourceFolder = null;
        }
        return true;
    }

    private void generateFileAndFolderList(File node) {
        if (node.isFile()) {
            fileList.add(generateZipEntry(node.getAbsoluteFile().toString()));
        }
        if (node.isDirectory()) {
            String dir = node.getAbsoluteFile().toString();
            fileList.add(dir.substring(sourceFolder.length(), dir.length()) + File.separator);

            String[] subNode = node.list();
            for (String fileOrFolderName : subNode) {
                generateFileAndFolderList(new File(node, fileOrFolderName));
            }
        }
    }

    private void updateSourceFolder(File node) {
        if (node.isFile() || node.isDirectory()) {
            String sf = node.getAbsoluteFile().toString();
            sourceFolder = sf.substring(0, (sf.lastIndexOf("/") > 0 ? sf.lastIndexOf("/") : sf.lastIndexOf("\\")));
            sourceFolder += File.separator;
        } else
            sourceFolder = null;
    }

    private String generateZipEntry(String file) {
        return file.substring(sourceFolder.length(), file.length());
    }

答案 11 :(得分：1)

此方法压缩文件夹并将所有子文件和文件夹（包括空文件夹）添加到zip文件中。

void zipFolder(Path sourceDir, Path targetFile) throws IOException {
    ZipDirectoryVisitor zipVisitor = new ZipDirectoryVisitor(sourceDir);
    Files.walkFileTree(sourceDir, zipVisitor);
    FileOutputStream fos = new FileOutputStream(targetFile.toString());
    ZipOutputStream zos = new ZipOutputStream(fos);
    byte[] buffer = new byte[1024];
    for (ZipEntry entry : zipVisitor.getZipEntries()) {
        zos.putNextEntry(entry);
        Path curFile = Paths.get(sourceDir.getParent().toString(), entry.toString());
        if (!curFile.toFile().isDirectory()) {
            FileInputStream in = new FileInputStream(Paths.get(sourceDir.getParent().toString(), entry.toString()).toString());
            int len;
            while ((len = in.read(buffer)) > 0) {
                zos.write(buffer, 0, len);
            }
            in.close();
        }
        zos.closeEntry();
    }
    zos.close();

}

这是ZipDirectoryVisitor实现：

class ZipDirectoryVisitor extends SimpleFileVisitor<Path> {
    private Path dirToZip;
    private List<ZipEntry> zipEntries; // files and folders inside source folder as zip entries
    public ZipDirectoryVisitor(Path dirToZip) throws IOException {
        this.dirToZip = dirToZip;
        zipEntries = new ArrayList<>();
    }

    @Override
    public FileVisitResult visitFile(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
        // According to zip standard backslashes
        // should not be used in zip entries
        String zipFile = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
        ZipEntry entry = new ZipEntry(zipFile);
        zipEntries.add(entry);
        return FileVisitResult.CONTINUE;
    }


    @Override
    public FileVisitResult preVisitDirectory(Path path, BasicFileAttributes basicFileAttributes) throws IOException {
        String zipDir = dirToZip.getParent().relativize(path).toString().replace("\\", "/");
        // Zip directory entries should end with a forward slash
        ZipEntry entry = new ZipEntry(zipDir + "/");
        zipEntries.add(entry);
        return FileVisitResult.CONTINUE;
    }


    @Override
    public FileVisitResult visitFileFailed(Path path, IOException e) throws IOException {
        System.err.format("Could not visit file %s while creating a file list from file tree", path);
        return FileVisitResult.TERMINATE;
    }

    public List<ZipEntry> getZipEntries() {
        return zipEntries;
    }
}

答案 12 :(得分：1)

使用zip4j，您可以轻松完成此操作

 mask = createNumberMask({
     allowDecimal: true,
     prefix: '',
     suffix: '',
     thousandsSeparatorSymbol: ' ',
     integerLimit: 13,
   });

它将存档您的文件夹及其中的所有内容。

使用ZipFile zipfile = new ZipFile(new File("D:\\reports\\january\\filename.zip")); zipfile.addFolder(new File("D:\\reports\\january\\")); 方法将其全部发挥出来：

.extractAll

答案 13 :(得分：0)

我修改了上述解决方案，并将Files.walk替换为Files.list。这还假定您要压缩的目录仅包含文件，而不包含任何子目录。

private void zipDirectory(Path dirPath) throws IOException {
        String zipFilePathStr = dirPath.toString() + ".zip";
        Path zipFilePath = Files.createFile(Paths.get(zipFilePathStr));

        try (ZipOutputStream zs = new ZipOutputStream(Files.newOutputStream(zipFilePath))) {
            Files.list(dirPath)
                .filter(filePath-> !Files.isDirectory(filePath))
                .forEach(filePath-> {
                    ZipEntry zipEntry = new ZipEntry(dirPath.relativize(filePath).toString());
                    try {
                        zs.putNextEntry(zipEntry);
                        Files.copy(filePath, zs);
                        zs.closeEntry();
                    }
                    catch (IOException e) {
                        System.err.println(e);
                    }
                });
        }
    }

答案 14 :(得分：0)

改进@Nikita Koksharov 的代码在打包空目录时出现问题。

private void zipDirectory(OutputStream outputStream, Path directoryPath) throws IOException {
    try (ZipOutputStream zs = new ZipOutputStream(outputStream)) {
        Path pp = directoryPath;
        Files.walk(pp)
                .forEach(path -> {
                    try {
                        if (Files.isDirectory(path)) {
                            zs.putNextEntry(new ZipEntry(pp.relativize(path).toString() + "/"));
                        } else {
                            ZipEntry zipEntry = new ZipEntry(pp.relativize(path).toString());
                            zs.putNextEntry(zipEntry);
                            Files.copy(path, zs);
                            zs.closeEntry();
                        }
                    } catch (IOException e) {
                        System.err.println(e);
                    }
                });
    }
}

测试使用

    FileOutputStream zipOutput = new FileOutputStream("path_to_file.zip");
    Path pathOutput = Path.of("path_directory_fid");
    zipDirectory(outputStream, pathOutput);

答案 15 :(得分：0)

试试这个 zip("C:\testFolder", "D:\testZip.zip")

public void zip( String sourcDirPath,  String zipPath) throws IOException {
  Path zipFile = Files.createFile(Paths.get(zipPath));

  Path sourceDirPath = Paths.get(sourcDirPath);
  try (ZipOutputStream zipOutputStream = new ZipOutputStream(Files.newOutputStream(zipFile));
       Stream<Path> paths = Files.walk(sourceDirPath)) {
      paths
              .filter(path -> !Files.isDirectory(path))
              .forEach(path -> {
                  ZipEntry zipEntry = new ZipEntry(sourceDirPath.relativize(path).toString());
                  try {
                      zipOutputStream.putNextEntry(zipEntry);
                      Files.copy(path, zipOutputStream);
                      zipOutputStream.closeEntry();
                  } catch (IOException e) {
                      System.err.println(e);
                  }
              });
  }

  System.out.println("Zip is created at : "+zipFile);
}
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