python二进制搜索树

时间:2013-04-12 08:51:05

标签: python search binary-tree binary-search-tree

出于某种原因,我似乎无法使用“查找”方法。我认为这与范围问题有关... root.val似乎并没有全局更新。我收到一条错误消息,说AtributeError:'int'对象没有属性'val' 这是我目前的代码:

class BinaryNode:
    def __init__(self, v):
        self.val = v
        self.leftChild = None
        self.rightChild = None
    def get(self):
        return self.val
    def set(self, v):
        self.val = v
    def getChildren(self):
        children = []
        if self.leftChild != None:
            children.append(self.leftChild)
        if self.rightChild != None:
            children.append(self.rightChild)
        return children

class Tree:
    def __init__(self):
        self.root = None
    def setRoot(self, node):
        self.root = node
    def size(self):
        if self.root == None:
            return 0
    def subtreeSize(node):
        return 1 + sum(subtreeSize(c) for c in node.getChildren())
        return subtreeSize(self.root)

class BinarySearchTree(Tree):
    def insert(self, val):
        self.insertNode(self.root, val)

    def insertNode(self, node, val):
        if node is None:
            self.setRoot(BinaryNode(val))
        elif val <= node.val:
            node.leftChild = insertNode(BinaryNode(val), val)
        elif val > node.val:
            node.rightChild = insertNode(BinaryNode(val), val)
        else:
            node.val = val


    def find(self, val):
        self.findNode(self.root, val)

    def findNode(self, node, val):
        if node is None:
            return False
        elif val == node.val:
            return True
        elif val < node.val:
            self.findNode(val, node.leftChild)
        else:
            self.findNode(val, node.rightChild)


if __name__ == "__main__":
    btree = BinarySearchTree()
    vals = [5]
    for v in vals:
        btree.insert(v)
    tests = [8, 5]
    for t in tests:
        print "find(%i) = %s" % (t, ("True" if btree.find(t) else "False"))

2 个答案:

答案 0 :(得分:5)

findNode()方法存在两个问题:

  1. 当您递归调用时,交换 nodeval个参数。这会导致您的代码尝试在整数值而不是节点上查找.val

  2. 您忘记返回递归调用结果。

  3. 更正的方法:

    def find(self, val):
        return self.findNode(self.root, val)
    
    def findNode(self, node, val):
        if node is None:
            return False
        elif val == node.val:
            return True
        elif val < node.val:
            return self.findNode(node.leftChild, val)
        else:
            return self.findNode(node.rightChild, val)
    

    您的下一个问题是insertNode方法;你试图在其中调用全局insertNode()函数;那可能应该是self.insertNode()。但是,该方法的没有返回值,因此您最终将node.leftChildnode.rightChild设置为None

    您只想将搜索插入点移交给递归调用,无需使用返回值:

    def insert(self, val):
        if self.root is None:
            self.setRoot(BinaryNode(val))
        else:
            self.insertNode(self.root, val)
    
    def insertNode(self, node, val):
        if val <= node.val:
            if node.leftChild:
                self.insertNode(node.leftChild, val)
            else:
                node.leftChild = BinaryNode(val)
        elif val > node.val:
            if node.rightChild:
                self.insertNode(node.rightChild, val)
            else:
                node.rightChild = BinaryNode(val)
    

    通过这些更改,您可以打印简单的测试:

    find(8) = False
    find(5) = True
    

答案 1 :(得分:0)

findNode()的一个问题是您缺少return语句。在

    elif val < node.val:
        self.findNode(val, node.leftChild)
    else:
        self.findNode(val, node.rightChild)

应该阅读

    elif val < node.val:
        return self.findNode(val, node.leftChild)
    else:
        return self.findNode(val, node.rightChild)

insertNode()中存在类似的问题。

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