Question

WITH x AS 
(
  SELECT *, 
    rn = ROW_NUMBER() OVER (PARTITION BY PersonRFID ORDER BY DateStamp)
  FROM AISDb
where action = 'IN'
) ,
y As
(
  SELECT *, 
    rna = ROW_NUMBER() OVER (PARTITION BY PersonRFID ORDER BY DateStamp)
  FROM AISDb
where action='OUT'
) 

SELECT y.ID,x.ID,x.PersonName,y.PersonName,x.PersonRFID, DATEDIFF(MINUTE, x.TimeStamp, y.TimeStamp) 
FROM x , y      
where x.PersonRFID = y.PersonRFID
And x.rn=y.rna
AND  cast(x.Datestamp as date) = cast(y.Datestamp as date)
Order By x.PersonName;

当我执行上述查询时，我得到下表：

   Datestamp         personName                     ID             TimeDifference

    1/30/2013   Aman Ullah Khan     E2001026770D01432810029D            11
    1/30/2013   Aman Ullah Khan     E2001026770D01432810029D            0
    1/30/2013   Aman Ullah Khan     E2001026770D01432810029D            1
    1/30/2013   Amjad Ali Anjum     E2001026770D024125401476            0
    1/30/2013   Amjad Ali Anjum     E2001026770D024125401476            1
    2/9/2013    Amjad Ali Anjum     E2001026770D024125401476            31
    2/10/2013   Amjad Ali Anjum     E2001026770D024125401476            3
    2/10/2013   Amjad Ali Anjum     E2001026770D024125401476            0
    2/10/2013   Amjad Ali Anjum     E2001026770D024125401476            3 
    1/30/2013   Arif Shah           E2001026770D01852370206D            0
    3/13/2013   Asmat Ullah         E2001026770D007624101DA1          456
    3/20/2013   Asmat Ullah         E2001026770D007624101DA1          558

正如你所看到的，例如人名“amanullah khan”有3个相同日期的记录，即2013年1月30日，但我需要一个记录，如果日期相同，我会得到'时差'

 1/30/2013   Aman Ullah Khan     E2001026770D01432810029D            14

Answer 1

试试这个 -

SELECT  y.ID ,
            x.ID ,
            x.PersonName ,
            y.PersonName ,
            x.PersonRFID ,
            SUM(DATEDIFF(MINUTE, x.TimeStamp, y.TimeStamp))
    FROM x
    JOIN y ON x.PersonRFID = y.PersonRFID
            AND x.rn = y.rna
            AND CAST(x.Datestamp AS DATE) = CAST(y.Datestamp AS DATE)
    GROUP BY y.ID ,
            x.ID ,
            x.PersonName ,
            y.PersonName ,
            x.PersonRFID
    ORDER BY x.PersonName

Answer 2

您需要更改如下

 SELECT y.ID,x.ID,x.PersonName,y.PersonName,x.PersonRFID,sum(DATEDIFF(MINUTE, x.TimeStamp, y.TimeStamp))
FROM x , y      
where x.PersonRFID = y.PersonRFID
And x.rn=y.rna
AND  cast(x.Datestamp as date) = cast(y.Datestamp as date)
group by
y.ID,x.ID,x.PersonName,y.PersonName,x.PersonRFID
Order By x.PersonName;

和相同日期记录的时差

2 个答案: