我为lightOpenId修改了google-example连接代码:
<?php
require_once('../db.php');
session_start();
# Logging in with Google accounts requires setting special identity, so this example shows how to do it.
require 'openid.php';
try {
# Change 'localhost' to your domain name.
$openid = new LightOpenID('127.0.0.1');
if(!$openid->mode) {
if(isset($_GET['login'])) {
$openid->identity = 'https://www.google.com/accounts/o8/id';
$openid->required = array('contact/email');
$openid->optional = array('namePerson', 'namePerson/friendly');
header('Location: ' . $openid->authUrl());
}
?>
<form action="?login" method="post">
<button>Login with Google</button>
</form>
<?php
} elseif($openid->mode == 'cancel') {
echo 'User has canceled authentication!';
} else {
if ($openid->validate()) {
$_SESSION['auth'] = $openid->identity;
$userinfo = $openid->getAttributes();
print_r($openid->required);
echo $_SESSION['auth'];
$stmt = $dbh->prepare("INSERT INTO users(id,name,email) VALUES(:id,:name,:email)");
$stmt->execute(array(":id" => $openid->identity,
":name" => "name",
":email" => "name"));
}
}
} catch(ErrorException $e) {
echo $e->getMessage();
}
我的问题是$ openid-&gt; required不会返回任何内容。该数组本身甚至不包含空的“联系人/电子邮件”字段。我在这里做错了什么?
答案 0 :(得分:0)
$openid->required
不会在请求之间保留,但您不必使用它。
至于$userinfo
为空,它只包含提供者返回的字段(例如,没有字段),无论您请求什么。
提供程序可能会返回您请求的字段,但它不必返回,甚至不必支持返回任何其他数据(因为这是协议扩展)。