Question

我有一个像

这样的字符串列表

[ABC].[XXX].sdfnwoaenwaf
[ABC].[XXX].sdfnwoaenwaf
[ABC].[XX1].sdfnwoaenwaf
[ABC].[XX1].sdfnwoaenwaf
[AB1].[XX3].sdfnwoaenwaf
[AB2].[XX1].sdfnwoaenwaf

如何在第二个点之前获得所有内容？例如第一个[ABC].[XXX]。

Answer 1

(.*)\.是您需要的正则表达式。您可以在http://regexhero.net/tester/

上进行测试

Answer 2

您可以尝试使用正则表达式或使用String类的LastIndexOf方法或String类的Split方法。

正则表达式

var toMatch = "[ABC].[XXX].sdfnwoaenwaf";

var pattern = new Regex("(.*?\\..*?)(:?\\.)");

var beforeSecondDot = pattern.Match(toMatch);

var stringBeforeSecondDot = beforeSecondDot.Groups[1].Value;

String.LastIndexOf

var toMatch = "[ABC].[XXX].sdfnwoaenwaf";

var indexOfLastDot = toMatch.LastIndexOf('.');

var beforeSecondDot = toMatch.Substring(0, indexOfLastDot);

String.Split

var toMatch = "[ABC].[XXX].sdfnwoaenwaf";

var parts = toMatch.Split('.');

var beforeSecondDot = String.Join(".", parts.Take(2));

Answer 3

string x = "[AB2].[XX1].sdfnwoaenwaf";

Regex regex = new Regex("([^.]+\\.[^.]+)\\.");
Match match = regex.Match(x);
if (match.Success)
{
    Console.WriteLine(match.Groups[1].Value);
}

输出：

[AB2].[XX1]

Answer 4

List<string> finalStrings = new List<string>();
List<string> strings = new List<string>();
strings.Add("[ABC].[XXX].sdfnwoaenwaf");
strings.Add("[ABC].[XXX].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");
strings.Add("[ABC].[XX3].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");

foreach (var item in strings)
{
     Regex rex = new Regex("(.*)\\.");
     string[] y = rex.Split(item);
     finalStrings.Add(y[1]);
}

使用正则表达式获取第二个给定角色前的所有内容

4 个答案: