Question

我正在编写一个应用程序，我需要从开始时间选择器获取用户设置时间，以及用户从结束时间选择器设置时间。然后将开始时间和结束时间与当前时间进行比较。如果当前时间等于开始时间，则静音电话。如果结束时间等于当前时间，请将手机静音。任何帮助，特别是代码示例将不胜感激。提前谢谢。

public TimePickerDialog.OnTimeSetListener sTimeSetListener = new TimePickerDialog.OnTimeSetListener() {
        public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
            sHour = hourOfDay;
            sMinute = minute;
            updateDisplay();
            displayToast();

        }
    };

    public TimePickerDialog.OnTimeSetListener eTimeSetListener = new TimePickerDialog.OnTimeSetListener() {
        public void onTimeSet(TimePicker view, int hourOfDay, int minute) {
            eHour = hourOfDay;
            eMinute = minute;
            updateDisplayE();
            displayToastE();

        }
    };

    public void updateDisplay() {
        startTime.setText(new StringBuilder().append(pad(sHour)).append(":")
                .append(pad(sMinute)));
        final int compareStartHour = sHour;
        Log.e("beginning", "Value " + sHour);
    }

    public void updateDisplayE()
 {
        endTime.setText(new StringBuilder().append(pad(eHour)).append(":")
                .append(pad(eMinute)));
    }

    private void displayToast() {
        Toast.makeText(
                this,
                new StringBuilder().append("Time choosen is ").append(
                        startTime.getText()), Toast.LENGTH_SHORT).show();

    }

    private void displayToastE() {
        Toast.makeText(
                this,
                new StringBuilder().append("Time choosen is ").append(
                        endTime.getText()), Toast.LENGTH_SHORT).show();

    }

    private static String pad(int c) {
        if (c >= 10)
            return String.valueOf(c);
        else
            return "0" + String.valueOf(c);
    }

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.preset_edit);
        save = (Button) findViewById(R.id.btnSave);
        TextView eventTxt = (TextView) findViewById(R.id.txtViewEvent);
        startTime = (Button) findViewById(R.id.btnStartTime);
        endTime = (Button) findViewById(R.id.btnEndTime);

        startTime.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                showDialog(TIME_DIALOG_ID);
            }
        });

        endTime.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                showDialog(TIME_DIALOG_ID2);
            }
        });

Answer 1

使用Calendar类实例：

Calendar calendar=Calendar.getInstance();
calendar.set(Calendar.HOUR, tPicker.getCurrentHour());
calendar.set(Calendar.MINUTE, tPicker.getCurrentMinute());
calendar.set(Calendar.SECOND, tPicker.getCurrentSecond());
//you can also set the day, month, year etc., default values are today's

然后致电

calendar.getTimeInMillis()

将以毫秒（long）返回时间值，您可以轻松地将其与另一个进行比较。

有关详细信息，请参阅Calendar课程文档。

Answer 2

从TimePicker获取时间并保存：

Time selectedTime = new Time(sHour, sMinute, 0);

将其与当前时间或任何其他时间进行比较：

Date time = MyClassName.convertStringToTime(selectedTime.toString());

并将两个日期值传递给函数：

public static int compareTime(Date date1, Date date2) {
        int result = date1.compareTo(date2);

        if (result > 0) //
        {
            return 1;
        } else if (result == 0) {
            return 0;
        }
        return -1;

    }

编辑： public static class MyClassName { public static Date convertStringToTime（String strTime） { System.out.println（“转换时间：”+ strTime +“。”）; Date dateTobeReturned = null;

            DateFormat sdf = new SimpleDateFormat(DateUtility.TIME_FORMAT);

            try {
                dateTobeReturned = sdf.parse(strTime);
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            System.out.println("Time: " + sdf.format(dateTobeReturned));


            return dateTobeReturned;
        }
    }

请问您是否有任何疑问。希望它有所帮助。

Answer 3

你也可以尝试这个..它对我有用...首先从TimePickerDialog中抽出一段时间，然后将其变为String，然后应用以下代码..

SimpleDateFormat sdf = new SimpleDateFormat("hh:mm");
            java.util.Date d_min = null;
            java.util.Date d_max = null;
            try {
                d_min = sdf.parse(time_min);//time_min is the Minimum time in String
                d_max = sdf.parse(time_max);time_max is the Maximun time in String
                d_compare = d_max.compareTo(d_min);
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
 if (d_compare < 0) {
                check = 3;
                showDialog(0);
            }

你可以像这样比较当前时间..希望这会对你有帮助.. 你也可以看一下...... current time

这...... link

如何从时间选择器中节省时间并进行比较

3 个答案: