我正在使用LINQPad
来评估我的linq查询。我的查询是这样的:
from o in MyTableFirst
join p in MyTableSecond on o.TheName equals p.TheName
where p.TheName == "CBA-123" && !p.Removed &&
(o.ReturnPeriod ==100 || o.ReturnPeriod ==10)
select new {
HMax1 = o.MaxValue1,
HMax2 = o.MaxValue2,
HMax3 = o.MaxValue3
}
此查询可以返回0或某些行数。
在LINQPad中,它返回我这样的东西:
HMax1 的 HMax2 的 HMax3
21.1 空 22.5
空 24.6 11.5
现在,我将如何获得这些返回行的最大值&列?
我期待 24.6 的回归。
谢谢你
答案 0 :(得分:2)
这个怎么样:
(from o in db.MyTableFirsts
join p in db.MyTableSeconds on o.TheName equals p.TheName
where p.TheName == "CBA-123" && !p.Removed &&
(o.ReturnPeriod == 100 || o.ReturnPeriod == 10)
select new
{
Maximum = Math.Max(
Math.Max((float)(o.MaxValue1 ?? 0), (float)(o.MaxValue2 ?? 0)),
(float)(o.MaxValue3 ?? 0)
)
}).OrderByDescending(o => o.Maximum).FirstOrDefault();
或者代替.OrderByDescending(o => o.Maximum).FirstOrDefault(),你可以使用.Max(o => o)
答案 1 :(得分:1)
试试这个:
(
from o in MyTableFirst
join p in MyTableSecond on o.TheName equals p.TheName
where p.TheName == "CBA-123" && !p.Removed &&
(o.Level ==100 || o.Level ==10)
//combine all of the numbers into one list
let listOfNumbers = new List<double?>{o.MaxValue1,o.MaxValue2,o.MaxValue3}
//select the list
select listOfNumbers
)
.SelectMany(c => c) //combine all the lists into one big list
.Max(c => c) //take the highst number