我正试图捕捉greenlets中提出的异常。根据{{3}},不幸的是,在Greenlet中提出的例外情况,留在Greenlet内部。在下面的代码中,我有一个同步方法,它产生爬行greenlets。那些爬行greenlets引发HTTPError异常,我需要在同步方法体中捕获。基于异常,在sync方法中,我将设置Account对象的适当状态。任何想法我怎么能在sync方法中捕获greenlets中引发的异常才能实现呢?先感谢您!
# this is standalone helper method
def crawl(item):
try:
item.refresh_children(False) # THROWS HTTPError exception
greenlets = [gevent.spawn_link_exception(crawl, child) for child in item.children]
gevent.joinall(greenlets)
except HTTPError, e:
print e.message
raise e
except (JSONDecodeError, InvalidCredentialsException) as e:
print e.message
raise e
# this is instance method of the Account class
def sync(self):
"Sync search index with data from source"
try:
greenlets = [gevent.spawn_link_exception(crawl, item) for item in self.get_navigation()]
gevent.joinall(greenlets)
self.date_synced = datetime.datetime.now()
self.save()
except HTTPError, e:
if e.status_code == 401:
self.status = 'revoked'
else:
self.status = 'error'
self.save()
except LinkedFailed, e:
print e.message
exception_name = e.message.split()[-1]
if exception_name in ['HTTPError', 'JSONDecodeError']:
self.status = 'error'
self.save()
elif exception_name == 'InvalidCredentialsException':
self.status = 'revoked'
self.save()
答案 0 :(得分:2)
Greenlets将保留为greenlet或异常生成的函数的结果(如果有的话)。您可以使用get
方法获取结果或重新引发异常。
由于您似乎正在根据任何错误更改状态,因此同步方法最终会显示如下内容:
def sync(self):
"Sync search index with data from source"
greenlets = [gevent.spawn_link_exception(crawl, item) for item in self.get_navigation()]
gevent.joinall(greenlets)
try:
results = [greenlet.get() for greenlet in greenlets]
except HTTPError, e:
if e.status_code == 401:
self.status = 'revoked'
else:
self.status = 'error'
self.save()
except LinkedFailed, e:
print e.message
exception_name = e.message.split()[-1]
if exception_name in ['HTTPError', 'JSONDecodeError']:
self.status = 'error'
self.save()
elif exception_name == 'InvalidCredentialsException':
self.status = 'revoked'
self.save()
self.date_synced = datetime.datetime.now()
self.save()