Question

我有一个下拉列表，其中填充了数据库“products”中的“product_name”列。

这些产品中的每一种都具有完成水平，“良好”，“更好”，“最佳”，具有与该水平相关的不同价格。（即产品1在3个单独的列中有3种不同的价格）

我想在下拉菜单下方标有“好”，“更好”，“最佳”的单选按钮，这些按钮会选择“产品名称”，并在与所选单选按钮完成关联的数据库表中查找价格将该值放入用户可以看到的单选按钮下方的文本框中，但显然不能编辑。

如果用户更改下拉菜单的选择，我希望它能够实时刷新。

这一切都在最后提交给php页面的表单上，该页面用于计算发票的数学。

Answer 1

需要太多背景知识才能在一个问题中回答这个问题。

你应该从了解javascript开始。这里有一个很好的教程：http://www.w3schools.com/js/

当您对此感觉良好时，请在此处了解AJAX：http://www.w3schools.com/ajax/default.asp

您应该在受影响的控件（单选按钮和下拉列表）上查找onChange事件，并在其中一个值更改时触发AJAX调用，这将为您提供要放在第三个输入字段中的结果。

希望这可以帮助你：）

Answer 2

这有效：

<?php
//***************************************
// This is downloaded from www.plus2net.com //
/// You can distribute this code with the link to www.plus2net.com ///
//  Please don't  remove the link to www.plus2net.com ///
// This is for your learning only not for commercial use. ///////
//The author is not responsible for any type of loss or problem or damage on using this script.//
/// You can use it at your own risk. /////
//*****************************************

$dbservertype='mysql';
$servername='localhost';
// username and password to log onto db server
$dbusername='';
$dbpassword='';
// name of database
$dbname='dd';

////////////////////////////////////////
////// DONOT EDIT BELOW  /////////
///////////////////////////////////////

connecttodb($servername,$dbname,$dbusername,$dbpassword);

function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
}
//////// End of connecting to database ////////
?>

<!doctype html public "-//w3c//dtd html 3.2//en">

<html>

<head>
<title>Multiple drop down list box from plus2net</title>




<SCRIPT language=JavaScript>

function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
self.location='dd.php?cat=' + val ;
}

</script>




</head>

<body>
<?

/*
If register_global is off in your server then after reloading of the page to get the value of cat from query string we have to take special care.
To read more on register_global visit.
http://www.plus2net.com/php_tutorial/register-globals.php
*/


@$cat=$_GET['cat']; // Use this line or below line if register_global is off
if(strlen($cat) > 0 and !is_numeric($cat)){ // to check if $cat is numeric data or     not. 
echo "Data Error";
exit;
}


//@$cat=$HTTP_GET_VARS['cat']; // Use this line or above line if register_global is off

///////// Getting the data from Mysql table for first list box//////////
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category"); 
///////////// End of query for first list box////////////

/////// for second drop down list we will check if category is selected else we will display all the subcategory///// 
if(isset($cat) and strlen($cat) > 0)
    {
$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory where cat_id=$cat order by subcategory"); 
}
else
{
$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory order by subcategory");
} 
////////// end of query for second subcategory drop down list box     ///////////////////////////


echo "<form method=post name=f1 action='dd-check.php'>";
/// Add your form processing page address to action in above line. Example  action=dd-check.php////


//////////        Starting of first drop downlist /////////
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";

while($noticia2 = mysql_fetch_array($quer2))
{ 
if($noticia2['cat_id']==@$cat)
{
echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";
}
else
    {
    echo  "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";
    }
}
echo "</select>";
//////////////////  This will end the first drop down list ///////////



//////////        Starting of second drop downlist /////////
echo "<select name='subcat'><option value=''>Select one</option>";

while($noticia = mysql_fetch_array($quer)) 
    { 
    echo  "<option value='$noticia[subcategory]'>$noticia[subcategory]</option>";
    }

echo "</select>";
//////////////////  This will end the second drop down list ///////////



//// Add your other form fields as needed here/////



echo "<input type=submit value=Submit>";
echo "</form>";
?>

<center><a href='http://www.plus2net.com'>PHP SQL HTML free tutorials and scripts</a>     
</center> 
</body>

</html>

使用表单上的php / mysql数据库查询和单选按钮实时刷新

2 个答案: