Question

根据示例，这是我的代码：我一直在寻找格式化Map中的Date字段但它抛出了这个例外：

The object [{birthDate=1963-07-16 00:00:00.0}], of class [class org.hibernate.collection.internal.PersistentMap], could not be converted to [class it.cineca.jaxb.adapter.MyMapType].

实施例

import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.HashMap;
import java.util.Map;
import java.util.Map.Entry;

import javax.xml.bind.annotation.adapters.XmlAdapter;

public final class MyMapAdapter extends

   XmlAdapter<MyMapType,Map<String, Date>> {

   private SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy");

   @Override
   public MyMapType marshal(Map<String, Date> arg0) throws Exception {
      MyMapType myMapType = new MyMapType();
      for(Entry<String, Date> entry : arg0.entrySet()) {
         MyMapEntryType myMapEntryType =
            new MyMapEntryType();
         myMapEntryType.key = entry.getKey();
         myMapEntryType.value = dateFormat.parse(entry.getValue().toString());
         myMapEntryType.value = entry.getValue();
         myMapType.entry.add(myMapEntryType);
      }
      return myMapType;
   }

   @Override
   public Map<String, Date> unmarshal(MyMapType arg0) throws Exception {
      HashMap<String, Date> hashMap = new HashMap<String, Date>();

      for(MyMapEntryType myEntryType : arg0.entry) {
         hashMap.put(myEntryType.key, myEntryType.value);
      }
      return hashMap;
   }

}



import java.util.Date;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlValue;

public class MyMapEntryType {

   @XmlAttribute
   public String key;

   @XmlValue
   public Date value;

}


import java.util.ArrayList;
import java.util.List;

public class MyMapType {

   public List<MyMapEntryType> entry = 
      new ArrayList<MyMapEntryType>();

}

这是人物绑定文件

     <?xml version="1.0"?>
     <xml-bindings
        xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
        package-name="it.model"  xml-mapping-metadata-complete="true">
        <xml-schema
            element-form-default="QUALIFIED"/>
        <java-types>
            <java-type name="Person"  xml-accessor-type="NONE">
                <xml-root-element/>
                <xml-type prop-order="firstName lastName stringMap "/>
                <java-attributes>
nillable="true"/>
                    <xml-element java-attribute="stringMap" name="string-map" nillable="true"/>
                    <xml-element java-attribute="dateMap" name="date-map" nillable="true">
                        <xml-java-type-adapter value="it.cineca.jaxb.adapter.MyMapAdapter" />
                    </xml-element>                  
          <xml-element java-attribute="positionCurrentSet" name="position-current-set" nillable="true">
       <!-- UNLIKELY THIS DOESN'T PRODUCE EMPTY NODE -->
       <xml-null-policy xsi-nil-represents-null="true" empty-node-represents-null="true" null-representation-for-xml="EMPTY_NODE" is-set-performed-for-absent-node="true" />
                    </xml-element>                  
                </java-attributes>
            </java-type>
    </java-types>
    </xml-bindings>

那我怎么解决呢？我试过跟http://blog.bdoughan.com/2010/07/xmladapter-jaxbs-secret-weapon.html 发布，但我没有发现错误，这是相同的逻辑。

Answer 1

我认为你在MyMapAdapter中反转了参数类型。来自JAXB javadocs：

公共抽象类XmlAdapter＆lt; ValueType，BoundType＆gt;

BoundType - JAXB不知道如何处理的类型。编写适配器以允许此类型通过ValueType用作内存中表示。

ValueType - JAXB知道如何开箱即用的类型。

尝试将您的班级签名更改为MyMapAdapter extends XmlAdapter<Map<String, Date>, MyMapType>，并交换您的编组和解组方法。

希望这有帮助，

瑞克

Jaxb eclipse moxy Nullable in element和XmlAdapter with Map <string，date> </string，date>

1 个答案: