我在我的iPhone应用程序中使用Objective C中的加密类,但我很难从我的Android应用程序中获得在JAVA中工作的相同功能。我的加密代码如下:
NSString * _secret = @"password";
NSString * _key = @"1428324560542678";
StringEncryption *crypto = [[StringEncryption alloc] init];
NSData *_secretData = [_secret dataUsingEncoding:NSUTF8StringEncoding];
CCOptions padding = kCCOptionPKCS7Padding;
NSData *encryptedData = [crypto encrypt:_secretData key:[_key dataUsingEncoding:NSUTF8StringEncoding] padding:&padding];
我试图在JAVA中复制它,但是当我编码相同的数据时,我得到了一个不同的字符串。所以我做错了什么,但我无法弄清楚。这是我的JAVA代码:
byte[] key = "1428324560542678".getBytes();
Cipher c = null;
try {
c = Cipher.getInstance("AES/ECB/PKCS7Padding");
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
SecretKeySpec k = new SecretKeySpec(key, "AES");
try {
c.init(Cipher.ENCRYPT_MODE, k);
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
EditText tv1passwordText = (EditText) findViewById(R.id.password);
String password = URLEncoder.encode(tv1passwordText.getText().toString(), "UTF-8");
byte[] encryptedData = c.doFinal( password.getBytes());
谁能看到我哪里出错了?
根据以下评论,我添加了getBytes,但产生的字符串仍然不同:
byte[] key = null;
try {
key = "1428324560542678".getBytes("UTF-8");
} catch (UnsupportedEncodingException e2) {
// TODO Auto-generated catch block
e2.printStackTrace();
}
Cipher c = null;
try {
c = Cipher.getInstance("AES/ECB/PKCS7Padding");
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
SecretKeySpec k = new SecretKeySpec(key, "AES");
try {
c.init(Cipher.ENCRYPT_MODE, k);
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
EditText tv1passwordText = (EditText) findViewById(R.id.password);
byte[] password = tv1passwordText.getText().toString().getBytes("UTF-8");
byte[] encryptedData = c.doFinal(password);
答案 0 :(得分:7)
以下是加密和解密的示例:
public static SecretKey generateKey() throws NoSuchAlgorithmException, InvalidKeySpecException {
return secret = new SecretKeySpec(password.getBytes(), "AES");
}
public static byte[] encryptMsg(String message, SecretKey secret) throws NoSuchAlgorithmException, NoSuchPaddingException, InvalidKeyException, InvalidParameterSpecException, IllegalBlockSizeException, BadPaddingException, UnsupportedEncodingException {
/* Encrypt the message. */
Cipher cipher = null;
cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, secret);
byte[] cipherText = cipher.doFinal(message.getBytes("UTF-8"));
return cipherText;
}
public static String decryptMsg(byte[] cipherText, SecretKey secret) throws NoSuchPaddingException, NoSuchAlgorithmException, InvalidParameterSpecException, InvalidAlgorithmParameterException, InvalidKeyException, BadPaddingException, IllegalBlockSizeException, UnsupportedEncodingException {
/* Decrypt the message, given derived encContentValues and initialization vector. */
Cipher cipher = null;
cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, secret);
String decryptString = new String(cipher.doFinal(cipherText), "UTF-8");
return decryptString;
}
要加密:
SecretKey secret = EncUtil.generateKey();
EncUtil.encryptMsg(<String to Encrypt>, secret))
解密
EncUtil.decryptMsg(<byte[]>, secret))
答案 1 :(得分:0)
如果可能,您应该使用CBC或CTR,而不是使用ECB。 ECB is insecure
看起来您的Objective-C代码使用的是UTF-8编码,但您没有在Java代码中指定它。使用getBytes("UTF-8")
。
答案 2 :(得分:0)
我注意到的一件事在过去引起的问题是加密的iOS字符串实际上是"Hello World\0"
,例如在最后用加号为空的加密字符串。所以尝试在Java的字符串末尾添加\0
,看看它是否产生相同的结果。
此外,java上的URLEncoder
步骤可能会引入额外的控制字符以及iOS端不存在的其他内容。将此后的文本与进入iOS加密步骤的文本进行比较以确保它们完全相同可能是值得的