Question

我正在使用com.sun.codemodel来生成我的类并添加JSR303注释。这工作正常，除非我想添加@ Pattern.List注释。

field.annotate(Pattern.class).param("regexp", "some_expression");

这是目前生成的内容：

@Pattern(regexp = "first_expression", message = "first.Pattern.message")
@Pattern(regexp = "second_expression", message = "second.Pattern.message")
@Pattern(regexp = "third_expression", message = "third.Pattern.message")

这就是我想要生成的内容

@Pattern.List({
  @Pattern(regexp = "first_expression", message = "first.Pattern.message")
  @Pattern(regexp = "second_expression", message = "second.Pattern.message")
  @Pattern(regexp = "third_expression", message = "third.Pattern.message")
})

有人知道这是怎么做到的吗？

Answer 1

假设你想要@PatternList（list = {@Pattern ...}），你需要使用paramArray()方法：

JDefinedClass testme = codeModel._class("Testme");

JAnnotationUse patternListAnnotation = testme.annotate(Pattern.List.class);
JAnnotationArrayMember list = patternListAnnotation.paramArray("value");

list.annotate(Pattern.class).param("regexp", "first_expression").param("message", "first.Pattern.message");
list.annotate(Pattern.class).param("regexp", "second_expression").param("message", "second.Pattern.message");
list.annotate(Pattern.class).param("regexp", "third_expression").param("message", "third.Pattern.message");

输出以下内容：

@Pattern.List({
    @Pattern(regexp = "first_expression", message = "first.Pattern.message"),
    @Pattern(regexp = "second_expression", message = "second.Pattern.message"),
    @Pattern(regexp = "third_expression", message = "third.Pattern.message")
})
public class Testme {
}

对于示例代码中提示的字段，这应该是相同的。

CodeModel如何添加@ Pattern.List注释com.sun.codemodel

1 个答案: