动态生成的FileUploads无法提供选项

时间:2013-04-11 13:54:22

标签: c# asp.net file-upload controls findcontrol

我在ASPX页面添加了一些动态控件。我需要动态添加它们,因为控件的数量取决于数据库记录。

我正在使用UpdatePanel并动态添加控件:

void AddFileUploadFields()
{
    for (int i = 0; i < Helper.uploadFieldsCount; i++)
    {
        FileUpload fileUpload = new FileUpload();
        string controlId = DateTime.Now.Ticks.ToString();
        Thread.Sleep(10); // for non-equal ID for each control
        fileUpload.ID = controlId;
        uploadFormsId.Add(controlId);

        UpdatePanel1.ContentTemplateContainer.Controls.Add(fileUpload);
        PlaceHolder1.Controls.Add(fileUpload);
     }
}

然后从按钮,在asp-tag <asp:Button ... />中静态定义我正在尝试处理我要上传的文件信息:

void buttonUpload_Click(object sender, EventArgs e)
{
    var iEnum = uploadFormsId.GetEnumerator();
    List<UploadFormDetails> uploadsInfo = new List<UploadFormDetails>();
    List<string> generatedFileNames = new List<string>();
    bool wereErrors = false;

    while (iEnum.MoveNext())
    {
        FileUpload uploadForm = (FileUpload)FindControl(iEnum.Current.ToString());
        uploadsInfo.Add(new UploadFormDetails(uploadForm.ID, uploadForm.HasFile, uploadForm.FileName));
    }
...
}

主要问题确实发生在这里:

FileUpload uploadForm = (FileUpload)FindControl(iEnum.Current.ToString());

当我获得这样的控制权时,它的所有选项(例如.HasFile.FileName)都无法查看。它看起来像一个没有保存选项的新控件。当然,我正在为测试选择一些文件,请不要认为我是在尝试从空表格上传。

我该怎么办呢?我无法上传任何文件...

1 个答案:

答案 0 :(得分:0)

我找到了一个解决方案,但我得到的结果是以其他方式设计的,它不使用ASP.NET的Server controls,我处理了普通的HTML元素。

在ASPX页面中,我定义了:

<%
    for (int i = 0; i < Helper.uploadFieldsCount; i++)
    {
        Response.Write("<input type='file' id='uploadField" + i.ToString() + "' name='uploadField" + i.ToString() + "' class='file_1' /><br />");
    }
%>

runat在页面的主要形式中定义,开头:

<body>
    <form enctype="multipart/form-data" id="form1" runat="server">
...

CodeBehind我正在使用基于GUID的随机生成的名称上传新文件:

void buttonUpload_Click(object sender, EventArgs e)
{
    List<string> generatedFileNames = new List<string>();
    bool wereErrors = false;

    for (int i = 0; i < Helper.uploadFieldsCount; i++)
    {
        HttpPostedFile filePosted = Request.Files["uploadField" + i.ToString()];

        if (filePosted != null && filePosted.ContentLength > 0)
        {
            string fileNameApplication = System.IO.Path.GetFileName(filePosted.FileName);
            string fileExtensionApplication = System.IO.Path.GetExtension(fileNameApplication);
            string newFile = Guid.NewGuid().ToString() + fileExtensionApplication;
            string filePath = System.IO.Path.Combine(Server.MapPath("uploads"), newFile);

            if (fileNameApplication != String.Empty)
            {
                generatedFileNames.Add(newFile);
                filePosted.SaveAs(filePath);
            }
       }
...