Question

选择.dll文件并按OK时，浏览对话框将关闭并重新打开。再次打开并按OK后，它会毫无问题地获取值。

这是我的代码

private void btnBrowse_Click(object sender, EventArgs e) {
            OpenFileDialog dllDialog = new OpenFileDialog();
            dllDialog.Filter = "DLL Files|*.dll";
            dllDialog.InitialDirectory = @"C:\";
            dllDialog.Title = "Please select .dll file.";
            if (dllDialog.ShowDialog() == DialogResult.OK) {
                dllDialog.ShowDialog();
                tbRepTempLibrary.Text = dllDialog.FileName;

            } else { 
                MessageBox.Show("error");
            }
        }

Answer 1

你不应该拨打dllDialog.ShowDialog()两次，而是使用它：

if (dllDialog.ShowDialog() == DialogResult.OK)
{
  tbRepTempLibrary.Text = dllDialog.FileName;
}

如果用户单击取消因为不想选择文件而不显示error，则用户有权在不打开或选择文件的情况下取消，您只是不会继续执行操作; - ）

Answer 2

您正在拨打ShowDialog()两次。你应该这样做：

private void btnBrowse_Click(object sender, EventArgs e) {
        OpenFileDialog dllDialog = new OpenFileDialog();
        dllDialog.Filter = "DLL Files|*.dll";
        dllDialog.InitialDirectory = @"C:\";
        dllDialog.Title = "Please select .dll file.";
        if (dllDialog.ShowDialog() == DialogResult.OK) {
            tbRepTempLibrary.Text = dllDialog.FileName;

        } else { 
            MessageBox.Show("error");
        }
    }

Answer 3

你打电话给ShowDialog()两次。你应该删除第二个，

private void btnBrowse_Click(object sender, EventArgs e) 
{
    OpenFileDialog dllDialog = new OpenFileDialog();
    dllDialog.Filter = "DLL Files|*.dll";
    dllDialog.InitialDirectory = @"C:\";
    dllDialog.Title = "Please select .dll file.";
    if (dllDialog.ShowDialog() == DialogResult.OK) 
    {
        tbRepTempLibrary.Text = dllDialog.FileName;

    } else 
    { 
        MessageBox.Show("error");
    }
}

Answer 4

 if (dllDialog.ShowDialog() == DialogResult.OK) {
            dllDialog.ShowDialog(); // This shouldn't be here

您将对话框显示两次。

'OpenFileDialog'第一次没有取值

4 个答案: