我有2 NSMutableArrays
。第一个数组包含具有属性NSString *itemID
的自定义对象插件,第二个数组仅包含具有相同值NSString
的{{1}}个对象,但是在另一个顺序中。我需要按每个对象的itemID
属性排序第一个数组,它应该像第二个数组一样排序。
我怎么能这样做?
答案 0 :(得分:3)
guideArray = < YOUR SECOND ARRAY WITH STRING OBJECT >;
unsortedArray = < YOUR FIRST ARRAY WITH CUSTOM OBJECT >;
[unsortedArray sortUsingComparator:^(id o1, id o2) {
Items *item1 = o1;
Items *item2 = o2;
NSInteger idx1 = [guideArray indexOfObject:item1.ItemID];
NSInteger idx2 = [guideArray indexOfObject:item2.ItemID];
return idx1 - idx2;
}];
NSLog(@"%@",unsortedArray);
答案 1 :(得分:1)
将自定义对象存储在以itemID
为键的字典中,使用此字典作为查找对对象进行排序:
NSArray *objects; // your objects
NSMutableArray *hintArray; // your sorted IDs
NSMutableDictionary *lookupDict = [[NSMutableDictionary alloc] initWithCapacity:[objects count]];
NSMutableArray *sortedObjects = [[NSMutableArray alloc] initWithCapacity:[hintArray count]];
for (id object in objects) {
[lookupDict setValue:object forKey:[object itemID]];
}
for (id hint in hintArray) {
[sortedObjects addObject:[lookupDict valueForKey:hint]];
}
编辑:
使用inplace类objects
:
NSMutableArray *objects;
NSMutableArray *hintArray;
NSMutableDictionary *lookupDict = [[NSMutableDictionary alloc] initWithCapacity:[hintArray count]];
int i = 0;
for (NSString *itemID in hintArray) {
[lookupDict setValue:[NSNumber numberWithInt:i] forKey:itemID];
i++;
}
[objects sortUsingComparator:^NSComparisonResult(id obj1, id obj2) {
return [[lookupDict valueForKey:[obj1 itemID]] compare:[lookupDict valueForKey:[obj2 itemID]]];
}];
答案 2 :(得分:1)
您可以使用以下语法比较两个对象: -
[items sortUsingComparator:^NSComparisonResult(Attribute *obj1, Attribute *obj2)
{
return [[NSNumber numberWithInt:[stringOrder indexOfObject:obj1.itemID]] compare:[NSNumber numberWithInt:[stringOrder indexOfObject:obj2.itemID]]]
}];
或者您可以使用以下代码段:
NSArray* sortedKeys = [dict keysSortedByValueUsingComparator:^(id obj1, id obj2)
{
return [obj1 compareTo:obj2];
}
享受编程!