所以我想将链接表复制到MS Access 2003中的代码,结构和数据中。
代码为:VBA或C#。或其他任何事情..
更新:我希望ms访问的副本结构和数据行为能够保留主键。如果复制链接表,则可以选择将其粘贴为“结构和数据(本地表)” 这是我想用代码实现的。
答案 0 :(得分:6)
我的理解是DAO不支持十进制数据类型,但ADOX支持。这是一个更新的过程,它使用ADOX将模式复制到新表。
一个有趣的注意事项:Jet的OLEDB提供程序按字母顺序对列进行排序,而不是按照in this KB article解释的顺序排列。我并不担心保留序数位置,但您可能会在这种情况下更新此程序以满足您的需求。
为了使ADOX版本的代码能够正常工作,您需要设置对Microsoft ADO Ext的引用。 2.x用于DDL和安全性(其中x =版本号;我使用2.8来测试此过程)。您还需要引用ADO。
Public Sub CopySchemaAndData_ADOX(ByVal sourceTableName As String, ByVal destinationTableName As String)
On Error GoTo Err_Handler
Dim cn As ADODB.Connection
Dim cat As ADOX.Catalog
Dim sourceTable As ADOX.Table
Dim destinationTable As ADOX.Table
Set cn = CurrentProject.Connection
Set cat = New ADOX.Catalog
Set cat.ActiveConnection = cn
Set destinationTable = New ADOX.Table
destinationTable.Name = destinationTableName
Set sourceTable = cat.Tables(sourceTableName)
Dim col As ADOX.Column
For Each col In sourceTable.Columns
Dim newCol As ADOX.Column
Set newCol = New ADOX.Column
With newCol
.Name = col.Name
.Attributes = col.Attributes
.DefinedSize = col.DefinedSize
.NumericScale = col.NumericScale
.Precision = col.Precision
.Type = col.Type
End With
destinationTable.Columns.Append newCol
Next col
Dim key As ADOX.key
Dim newKey As ADOX.key
Dim KeyCol As ADOX.Column
Dim newKeyCol As ADOX.Column
For Each key In sourceTable.Keys
Set newKey = New ADOX.key
newKey.Name = key.Name
For Each KeyCol In key.Columns
Set newKeyCol = destinationTable.Columns(KeyCol.Name)
newKey.Columns.Append (newKeyCol)
Next KeyCol
destinationTable.Keys.Append newKey
Next key
cat.Tables.Append destinationTable
'Finally, copy data from source to destination table
Dim sql As String
sql = "INSERT INTO " & destinationTableName & " SELECT * FROM " & sourceTableName
CurrentDb.Execute sql
Err_Handler:
Set cat = Nothing
Set key = Nothing
Set col = Nothing
Set sourceTable = Nothing
Set destinationTable = Nothing
Set cn = Nothing
If Err.Number <> 0 Then
MsgBox Err.Number & ": " & Err.Description, vbCritical, Err.Source
End If
End Sub
这是原始的DAO程序
Public Sub CopySchemaAndData_DAO(SourceTable As String, DestinationTable As String)
On Error GoTo Err_Handler
Dim tblSource As DAO.TableDef
Dim fld As DAO.Field
Dim db As DAO.Database
Set db = CurrentDb
Set tblSource = db.TableDefs(SourceTable)
Dim tblDest As DAO.TableDef
Set tblDest = db.CreateTableDef(DestinationTable)
'Iterate over source table fields and add to new table
For Each fld In tblSource.Fields
Dim destField As DAO.Field
Set destField = tblDest.CreateField(fld.Name, fld.Type, fld.Size)
If fld.Type = 10 Then
'text, allow zero length
destField.AllowZeroLength = True
End If
tblDest.Fields.Append destField
Next fld
'Handle Indexes
Dim idx As Index
Dim iIndex As Integer
For iIndex = 0 To tblSource.Indexes.Count - 1
Set idx = tblSource.Indexes(iIndex)
Dim newIndex As Index
Set newIndex = tblDest.CreateIndex(idx.Name)
With newIndex
.Unique = idx.Unique
.Primary = idx.Primary
'Some Indexes are made up of more than one field
Dim iIdxFldCount As Integer
For iIdxFldCount = 0 To idx.Fields.Count - 1
.Fields.Append .CreateField(idx.Fields(iIdxFldCount).Name)
Next iIdxFldCount
End With
tblDest.Indexes.Append newIndex
Next iIndex
db.TableDefs.Append tblDest
'Finally, copy data from source to destination table
Dim sql As String
sql = "INSERT INTO " & DestinationTable & " SELECT * FROM " & SourceTable
db.Execute sql
Err_Handler:
Set fld = Nothing
Set destField = Nothing
Set tblDest = Nothing
Set tblSource = Nothing
Set db = Nothing
If Err.Number <> 0 Then
MsgBox Err.Number & ": " & Err.Description, vbCritical, Err.Source
End If
End Sub
答案 1 :(得分:0)
尝试docmd.CopyObject或docmd.TransferDatabase
答案 2 :(得分:-1)
创建此查询并执行
SELECT * INTO MyNewTable FROM LinkedTableName
在VBA中你可以做到
docmd.runsql "SELECT * INTO MyNewTable FROM LinkedTableName"
要保持结构,您必须DoCmd.TransferDatabase acImport