Question

我知道以下条件将返回过去7天的总数

SELECT count(id) FROM registration 
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()

我是否可以执行一个查询，以便在过去7天内返回每个日期的7个结果数组？

例如：

day 1 - 10
day 2 - 5
day 3 - 9
..
..
..

Answer 1

添加分组条款：

SELECT count(id), DATE(createdDate)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)

Answer 2

这将为您提供日期和计数。

SELECT DATE(createdDate),COUNT(id)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)

或者，为了使结果更接近您的示例，您可以使用：

SELECT CONCAT("Day ",DATEDIFF(NOW(), createdDate)) AS day,COUNT(id)
FROM registration
WHERE createdDate BETWEEN DATE_SUB(CURDATE(), INTERVAL 7 DAY) AND CURDATE()
GROUP BY DATE(createdDate)

Answer 3

select 8 - n day, count(id)
from registration
join (select 1 n union select 2 union select 3 union select 4 union select 5 union select 6 union select 7) x
on createdDate between date_sub(curdate(), interval n day) and date_sub(curdate(), interval n-1 day)
group by day
order by day

单个查询以获取过去7天的个人计数

3 个答案: