如何查找列表中唯一单词的数量

Question

例如：

["apple", "banana", "apple", "mango"]

Answer 1

字符串“join”方法在这里可能对您有用，但它不会为您提供您想要的答案。要将列表中的元素与“无”联系起来：

In [1]: "".join(["I","a","m","h","a","p","p","y"])
Out[1]: 'Iamhappy'

如果您的列表包含空格，您可以这样做：

In [2]: "".join(["I"," ","a","m"," ","h","a","p","p","y"])
Out[2]: 'I am happy'

后面跟着一个字符串“split”：

In [3]: 'I am happy'.split(" ")
Out[3]: ['I', 'am', 'happy']

但解析字典单词的原始结果（Out [1]）是另一回事。

Answer 2

您是否有关于如何组合列表中元素的定义？

所以，假设你有你的例子

x = ["I","a","m","h","a","p","p","y"]
comb = [1, 2, 5]

然后

def combine(l, comb):
    x = []

    if sum(comb) == len(l):
        for n, i in enumerate(comb):
            d = sum(comb[:n])
            x.append(''.join(l[d : d + i]))
        return x
    return l

和combine(x, comb)将返回['I', 'am', 'happy']。