数据超出Bounds Error Java

时间:2013-04-10 22:21:43

标签: java arrays int variable-assignment

这个第一个代码是我认为你需要关注的全部代码。剩下的代码是为了防止我遗漏的东西。

编辑:确实将第二个j更改为k可以解决问题。我循环j两次,我的数组的值太大了。谢谢!

public static void makeMove(){
    char[] path = new char[TicTacToeArray.length];
    int[][] DefensiveOppsArray = new int[TicTacToeArray.length][TicTacToeArray.length];

    for(int i=0; i < DefensiveOppsArray.length; i++){
        for(int j=0; j < DefensiveOppsArray.length; j++){
            DefensiveOppsArray[i][j] = 0;
        }
    }   

    for(int i=0; i < DefensiveOppsArray.length; i++){
        for(int j=0; j < DefensiveOppsArray.length; j++){
            //path for straight down
            for(j=0; j < DefensiveOppsArray.length; j++){
                path[j] = TicTacToeArray[i][j];}

                DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;


            }
        }
    }

我一直在为一个tic tac toe Java游戏做这个任务但是已经遇到了“线程中的异常”主“java.lang.ArrayIndexOutofBoundsException:3。这个错误来自行DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;。这必然意味着我在某种程度上没有正确定义我的DefensiveOppsArray的大小。我做错了什么?

TicTacToeArray继承自UserTicTacToe。测试类只是

public class Test3{

public static void main(String[] args){
    IntelligentTicTacToe2.promptUserTTT();
    }
}

我需要创建一个与TicTacToeArray长度相同的DefenseOppsArray,以便我可以操纵数字,这样我就可以确定最佳移动是什么。不幸的是,我正在努力简单地创建和操作DefenseOppsArray中的数字。

public class IntelligentTicTacToe2 extends UserTicTacToe{

public static void promptUserTTT(){

    //read the input size
    System.out.print("Enter TicTacToe Array Size: ");
    int size = UserInput.readInt();
    System.out.println("");

    //start the game
    UserTicTacToe.startTTT(size);

    //keep track of consecutive errors
    int consecutiveErrors = 0;

    //display the initial game board
    UserTicTacToe.displayTTT();

    //let the user keep playing forever if they want to
    while(true){
        //get the input symbol from the user
        System.out.print("Enter Symbol (X or O): ");
        String symbol = UserInput.readString();
        System.out.println("");
        //hopefully the string is just one character - if not get just
        //the first character
        char sym = '*';
        if(symbol.length() > 0){
            sym = symbol.charAt(0);
        }

        //if the symbol was a Q, then quit
        if(sym == 'Q'){
            break ;
        }

        //get the row and column
        System.out.print("Enter Row to Place Symbol: ");
        int row = UserInput.readInt();
        System.out.println("");
        System.out.print("Enter Col to Place Symbol: ");
        int col = UserInput.readInt();
        System.out.println("");

        //update the game board and see if input was valid
        boolean inputValid = UserTicTacToe.updateTTT(sym,row,col);

        //re-display the game board if input was accepted
        if(inputValid){
            UserTicTacToe.scoreTTT();
            UserTicTacToe.displayTTT();
            consecutiveErrors = 0;
        }
        //if input was rejected, print a message, increment error count,
        //and quit if we are on the 5th error
        else{
            System.out.println("Invalid Input!");
            if(consecutiveErrors >= 4){
                break ;
            }
            consecutiveErrors++;
        }
        makeMove();



    }
}

3 个答案:

答案 0 :(得分:2)

问题是你在嵌套循环中使用j两次作为计数器

这是出错的地方:

for(int i=0; i < DefensiveOppsArray.length; i++){
    for(int j=0; j < DefensiveOppsArray.length; j++){
        //path for straight down
        for(j=0; j < DefensiveOppsArray.length; j++){ // << here you use j again as counter
            path[j] = TicTacToeArray[i][j];
            DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;
        }
     }
}

也许你编写了一个循环太多了?

答案 1 :(得分:1)

你正在两次增加int j。

答案 2 :(得分:1)

问题确实是嵌套for循环,它重用j作为变量。代码的那部分应该格式化如下:

for(int i=0; i < DefensiveOppsArray.length; i++){
    for(int j=0; j < DefensiveOppsArray.length; j++){
        //path for straight down
        for(j=0; j < DefensiveOppsArray.length; j++){
            path[j] = TicTacToeArray[i][j];
        }

        DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;
    }
}

这清楚地说明了发生了什么 - j在内部for循环中被增加到3,所以当它到达下一行时它会抛出异常。我不知道你的意思是否适合

DefensiveOppsArray[i][j]=DefensiveOppsArray[i][j] + 1;

是否在内部for循环中,但即使您确实需要循环,也不要在内部j循环中重用for