我正在玩ServiceStack并且想知道它是否支持这种情况。我在我的请求类型中使用泛型,以便从公共接口继承的许多DTO将支持相同的基本方法[如... GetById(int Id)]。
使用特定于某种DTO的请求类型,但打破了泛型的好处......
var fetchedPerson = client.Get<PersonDto>(new PersonDtoGetById() { Id = person.Id });
Assert.That(person.Id, Is.EqualTo(fetchedPerson.Id)); //PASS
将路线映射到通用也有效:
Routes.Add<DtoGetById<PersonDto>>("/persons/{Id}", ApplyTo.Get);
...
var fetchedPerson2 = client.Get<PersonDto>(string.Format("/persons/{0}", person.Id));
Assert.That(person.Id, Is.EqualTo(fetchedPerson2.Id)); //PASS
但是使用端到端通用请求类型失败:
var fetchedPerson3 = client.Get<PersonDto>(new DtoGetById<PersonDto>() { Id = person.Id });
Assert.That(person.Id, Is.EqualTo(fetchedPerson3.Id)); //FAIL
我想知道我是否只是遗漏了一些东西,或者我是否想要将ooone层抽象得太远......:)
下面是一个完整的,失败的程序,使用NUnit,默认的ServiceStack东西:
namespace ssgenerics
{
using NUnit.Framework;
using ServiceStack.ServiceClient.Web;
using ServiceStack.ServiceHost;
using ServiceStack.ServiceInterface;
using ServiceStack.WebHost.Endpoints;
[TestFixture]
class Program
{
public static PersonDto GetNewTestPersonDto()
{
return new PersonDto()
{
Id = 123,
Name = "Joe Blow",
Occupation = "Software Developer"
};
}
static void Main(string[] args)
{}
[Test]
public void TestPutGet()
{
var listeningOn = "http://*:1337/";
var appHost = new AppHost();
appHost.Init();
appHost.Start(listeningOn);
try
{
var BaseUri = "http://localhost:1337/";
var client = new JsvServiceClient(BaseUri);
var person = GetNewTestPersonDto();
client.Put(person);
var fetchedPerson = client.Get<PersonDto>(new PersonDtoGetById() { Id = person.Id });
Assert.That(person.Id, Is.EqualTo(fetchedPerson.Id));
var fetchedPerson2 = client.Get<PersonDto>(string.Format("/persons/{0}", person.Id));
Assert.That(person.Id, Is.EqualTo(fetchedPerson2.Id));
Assert.That(person.Name, Is.EqualTo(fetchedPerson2.Name));
Assert.That(person.Occupation, Is.EqualTo(fetchedPerson2.Occupation));
var fetchedPerson3 = client.Get<PersonDto>(new DtoGetById<PersonDto>() { Id = person.Id });
Assert.That(person.Id, Is.EqualTo(fetchedPerson3.Id));
Assert.That(person.Name, Is.EqualTo(fetchedPerson3.Name));
Assert.That(person.Occupation, Is.EqualTo(fetchedPerson3.Occupation));
}
finally
{
appHost.Stop();
}
}
}
public interface IDto : IReturnVoid
{
int Id { get; set; }
}
public class PersonDto : IDto
{
public int Id { get; set; }
public string Name { get; set; }
public string Occupation { get; set; }
}
public class DtoGetById<T> : IReturn<T> where T : IDto { public int Id { get; set; } }
public class PersonDtoGetById : IReturn<PersonDto> { public int Id { get; set; } }
public abstract class DtoService<T> : Service where T : IDto
{
public abstract T Get(DtoGetById<T> Id);
public abstract void Put(T putter);
}
public class PersonService : DtoService<PersonDto>
{
public override PersonDto Get(DtoGetById<PersonDto> Id)
{
//--would retrieve from data persistence layer
return Program.GetNewTestPersonDto();
}
public PersonDto Get(PersonDtoGetById Id)
{
return Program.GetNewTestPersonDto();
}
public override void Put(PersonDto putter)
{
//--would persist to data persistence layer
}
}
public class AppHost : AppHostHttpListenerBase
{
public AppHost()
: base("Test HttpListener",
typeof(PersonService).Assembly
) { }
public override void Configure(Funq.Container container)
{
Routes.Add<DtoGetById<PersonDto>>("/persons/{Id}", ApplyTo.Get);
}
}
}
答案 0 :(得分:3)
不,ServiceStack中的一个基本概念是每个服务都需要自己的唯一请求DTO ,请参阅this answer for more examples on this。
你可以这样做:
[Route("/persons/{Id}", "GET")]
public class Persons : DtoGetById<Person> { ... }
但我强烈advise against using inheritance in DTOs。财产声明就像服务合同的DSL,而不是应隐藏的东西。
有关详细信息,请参阅此答案on the purpose of DTO's in Services。