我有一个像素数组,我需要转换为HBITMAP才能在窗口中显示它。 我尝试使用CreateDIBitmap()但我没有BMP标头。 我尝试根据MSDN文档手动构建它们,但这不起作用。
这里我的代码看起来如何
HBITMAP hBitmap
char pixels[160*120]; // White grayscale image of size 160x120
memset(pixels,255,sizeof(pixels));
BITMAPINFOHEADER bmih;
bmih.biSize = sizeof(BITMAPINFOHEADER);
bmih.biWidth = 160;
bmih.biHeight = -120;
bmih.biPlanes = 1;
bmih.biBitCount = 8;
bmih.biCompression = BI_RGB ;
bmih.biSizeImage = 0;
bmih.biXPelsPerMeter = 10;
bmih.biYPelsPerMeter = 10;
bmih.biClrUsed =0;
bmih.biClrImportant =0;
BITMAPINFO dbmi;
dbmi.bmiHeader = bmih;
dbmi.bmiColors->rgbBlue = 0;
dbmi.bmiColors->rgbGreen = 0;
dbmi.bmiColors->rgbRed = 0;
dbmi.bmiColors->rgbReserved = 0;
void* bits = (void*)&(pixels[0]);
hBitmap = CreateDIBitmap(localDC, &bmih, CBM_INIT, qB.bmBits, &dbmi, DIB_RGB_COLORS);
现在我得到一个非NULL的hBitmap,它很好,但它总是显示黑色图像,好像它没有指向像素数组。 我使用代码
检查了它BITMAP qB;
GetObject(reinterpret_cast<HGDIOBJ>(hBitmap),sizeof(BITMAP),reinterpret_cast<LPVOID>(&qB));
确实qB.bmBits为NULL。 有什么问题以及如何解决?
答案 0 :(得分:6)
我找到了怎么做。
我们需要使用CreateDIBSection()
代替CreateDIBitmap()
所以这是工作代码
HBITMAP hBitmap = NULL;
unsigned char pixels[160*120*3];
for (int i=0; i<160*120*3; i++){
pixels[i] = (i%4==1)*255; // An BGR (not RGB) 160x120 image.
}
BITMAPINFOHEADER bmih;
bmih.biSize = sizeof(BITMAPINFOHEADER);
bmih.biWidth = 160;
bmih.biHeight = -120;
bmih.biPlanes = 1;
bmih.biBitCount = 24;
bmih.biCompression = BI_RGB ;
bmih.biSizeImage = 0;
bmih.biXPelsPerMeter = 10;
bmih.biYPelsPerMeter = 10;
bmih.biClrUsed =0;
bmih.biClrImportant =0;
BITMAPINFO dbmi;
ZeroMemory(&dbmi, sizeof(dbmi));
dbmi.bmiHeader = bmih;
dbmi.bmiColors->rgbBlue = 0;
dbmi.bmiColors->rgbGreen = 0;
dbmi.bmiColors->rgbRed = 0;
dbmi.bmiColors->rgbReserved = 0;
void* bits = (void*)&(pixels[0]);
// Create DIB
hBitmap = CreateDIBSection(localDC, &dbmi, DIB_RGB_COLORS, &bits, NULL, 0);
if (hBitmap == NULL) {
::MessageBox(NULL, __T("Could not load the desired image image"), __T("Error"), MB_OK);
return;
}
// copy pixels into DIB.
memcpy(bits,pixels,sizeof(pixels));
对于灰度图像,将像素复制到循环中而不是使用memcpy()
#define INTENSITY unsigned char
INTENSITY* dest = (INTENSITY*)bits;
const INTENSITY* src = .. Put your char array of pixels;
for (int j=0; j<imageWidth; j++){
for (int i=0; i<imageHeight; i++, src++){
*dest++ = *src;
*dest++ = *src;
*dest++ = *src;
}
// Padd the line to round WORD.
if (imageWidth%2)
*dest++ = 0;
}
答案 1 :(得分:4)
你的帖子非常有帮助(答案)然而它对我没有用,这里的代码有很小的修正:
// creating input
unsigned char pixels[160*120*3];
for (int i=0; i<160*120*3; i++)
pixels[i] = (i%4==1)*255; // An BGR (not RGB) 160x120 image.
// at this point we have some input
BITMAPINFOHEADER bmih;
bmih.biSize = sizeof(BITMAPINFOHEADER);
bmih.biWidth = 160;
bmih.biHeight = -120;
bmih.biPlanes = 1;
bmih.biBitCount = 24;
bmih.biCompression = BI_RGB ;
bmih.biSizeImage = 0;
bmih.biXPelsPerMeter = 10;
bmih.biYPelsPerMeter = 10;
bmih.biClrUsed =0;
bmih.biClrImportant =0;
BITMAPINFO dbmi;
ZeroMemory(&dbmi, sizeof(dbmi));
dbmi.bmiHeader = bmih;
dbmi.bmiColors->rgbBlue = 0;
dbmi.bmiColors->rgbGreen = 0;
dbmi.bmiColors->rgbRed = 0;
dbmi.bmiColors->rgbReserved = 0;
HDC hdc = ::GetDC(NULL);
HBITMAP hbmp = CreateDIBitmap(hdc, &bmih, CBM_INIT, pixels, &dbmi, DIB_RGB_COLORS);
if (hbmp == NULL) {
::MessageBox(NULL, L"Could not load the desired image image", L"Error", MB_OK);
return;
}
::ReleaseDC(NULL, hdc);
// a little test if everything is OK
OpenClipboard(NULL);
EmptyClipboard();
SetClipboardData(CF_BITMAP, hbmp);
CloseClipboard();
// cleanup
DeleteObject(hbmp);
答案 2 :(得分:0)
这里的其他答案非常有帮助,但最终我只用1行就可以实现它。
HBITMAP hBm = CreateBitmap(width,height,1,32,pixels); // 1 plane, 32 bits
希望对以后的读者有用。
此外,如果您需要使用设备上下文,则还有CreateCompatibleBitmap
和SetDIBits
。
在MSDN上CreateDIBitmap
声明:
使用fdwInit作为CBM_INIT调用CreateDIBitmap等效于 调用CreateCompatibleBitmap函数以在 设备的格式,然后调用SetDIBits函数以 将DIB位转换为DDB。