MySQL：在select语句中自动增加临时列

Question

如何使用MySQL在select语句中创建和自动增加临时列？

这是我到目前为止所做的：

SET @cnt = 0;
SELECT
    (@cnt =@cnt + 1) AS rowNumber,
    rowID
FROM myTable
WHERE CategoryID = 1

返回：

+++++++++++++++++++++
+ rowNumber | rowID +
+++++++++++++++++++++
+  (NULL)   |   1   +
+  (NULL)   |   25  +
+  (NULL)   |   33  +
+  (NULL)   |   150 +
+  (NULL)   |   219 +
+++++++++++++++++++++

但我需要：

+++++++++++++++++++++
+ rowNumber | rowID +
+++++++++++++++++++++
+  1        |   1   +
+  2        |   25  +
+  3        |   33  +
+  4        |   150 +
+  ...      |   ... +
+++++++++++++++++++++

Answer 1

这会为您提供带有3的 连续 行号。

SELECT
    (@cnt := @cnt + 1) AS rowNumber,
    t.rowID
FROM myTable AS t
  CROSS JOIN (SELECT @cnt := 0) AS dummy
WHERE t.CategoryID = 1
ORDER BY t.rowID ;

<强>结果

| ROWNUMBER | ROWID |
---------------------
|         1 |     1 |
|         2 |    25 |
|         3 |    33 |
|         4 |   150 |

Answer 2

试试这个：

SET @rownr=0;
SELECT @rownr:=@rownr+1 AS rowNumber, rowID
  FROM myTable
  WHERE CategoryID = 1

在现代版本的MySQL中，您可以使用MySQL窗口：http://www.mysqltutorial.org/mysql-window-functions/mysql-row_number-function/

示例：

SELECT  ROW_NUMBER() OVER (  ORDER BY productName  ) row_num, 
        productName, msrp 
FROM   products ORDER BY   productName;

Answer 3

但是如果你在select语句中有group by怎么办？计算将结束。

对于这种情况，我找到的唯一解决方案是嵌套选择：

SELECT (@cnt := @cnt + 1) AS rowNumber, t.*
from
(select
    t.rowID
FROM myTable 
WHERE CategoryID = 1
ORDER BY rowID) t
CROSS JOIN (SELECT @cnt := 0) AS dummy

Answer 4

您可以使用此代码。我认为这是一个更简单的解决方案。

select ROW_NUMBER() OVER (  ORDER BY id  ) AS Seid, id from table1 where id<10

结果：

|赛德 |身份证|

| 1 | 5|

| 2 | 7|

| 3 | 8|

| 4 | 9|