Question

我正在尝试使用天数输出数月（$ daydiff的价值）。

整个代码如下：

$ArrivalDate = $variants_data['ArrivalDate'];

$daydiff=floor((abs(strtotime(date("Y-m-d")) - strtotime($ArrivalDate))/(60*60*24)));


if (!empty($daydiff) &&  $ArrivalDate == '2013-12-25') {
    $ETA ='Date Not Confirmed';
} 

elseif (!empty($daydiff) &&  is_null($ArrivalDate)) {
    $ETA ='Not available';
}

elseif ( $daydiff > 30 && $daydiff < 60 ) { // anything between 31 and 59 days is 1 month
    $ETA ='1 Month';
}

elseif ( $daydiff > 60 &&  $daydiff < 90  )  { // anything between 61 and 89 days is 2 months
    $ETA ='2 Months';
}

else
{
    $ETA ='';
}

此部分代码未向我提供所需结果

elseif ( $daydiff > 30 && $daydiff < 60 ) { // anything between 31 and 59 days is 1 month
    $ETA ='1 Month';
}

elseif ( $daydiff > 60 &&  $daydiff < 90  )  { // anything between 61 and 89 days is 2 months
    $ETA ='2 Months';
}

else
{
$ETA ='';
}

我得到'未确认日期'作为结果。如果$ daydiff值落在范围内，则所需结果为“1个月”或“2个月”。

我在这里做错了什么？

Answer 1

试

    $ArrivalDate = $variants_data['ArrivalDate'];

if (!empty($ArrivalDate)){
    $ArrivalDate = date('Y-m-d', strtotime($ArrivalDate));

    $daydiff=floor(abs(strtotime(date("Y-m-d")) - strtotime($ArrivalDate)) / (60*60*24));

    echo $daydiff;

    if ($ArrivalDate == '2013-12-25') {
        $ETA ='Date Not Confirmed';
    }
    elseif ( $daydiff > 30 && $daydiff < 60 ) { // anything between 31 and 59 days is 1 month
        $ETA ='1 Month';
    }

    elseif ( $daydiff > 60 &&  $daydiff < 90  )  { // anything between 61 and 89 days is 2 months
        $ETA ='2 Months';
    }
    else
    {
        $ETA ='';
    }
} else {
    $ETA ='Not available';
}

Answer 2

试试这个这里是一个简单的例子来计算月份中的日期差异而没有额外的if else条件

<?php

$date1=date('2013-1-1');
$date2=date('2013-5-2');

echo "date1 :: ".$date1."<br>";
echo "date2 :: ".$date2."<br>";

$date_diff=strtotime($date2)-strtotime($date1);

echo "date difference in months => ".floor(($date_diff)/2628000)." months <br>";
?>

PHP的天数为几个月

2 个答案: