Convert.ToDecimal失败并说输入字符串的格式不正确

时间:2013-04-10 05:40:18

标签: c# asp.net asp.net-mvc asp.net-mvc-3

我有这个带有price属性的视图模型类。

问题是,如果用户输入值$200,150.90,则表示未格式化并发送给控制器。

对于十进制的默认模型格式化程序可能有什么问题?

public ItemViewModel
{

public string Name {get;set;}
[DisplayFormat(DataFormatString = "{0:c}")]
[RegularExpression(@"^\$?([0-9]{1,3},([0-9]{3},)*[0-9]{3}|[0-9]+)(.[0-9][0-9])?$"
ErrorMessage = "Enter a valid money value. 2 Decimals only allowed")]
public decimal? Price{ get; set; }
}

在视图中

@model ItemViewModel

@Html.TextBoxFor(m=>m.Price)

在控制器

public ActionResult Save(ItemViewModel model)
{

 // model.Price is always null, even if it has value $200,150.90
}

我已在Global.asax

中注册了此十进制模型活页夹
   ModelBinders.Binders.Add(typeof(decimal?), new DecimalModelBinder());

   public object BindModel(ControllerContext controllerContext,
        ModelBindingContext bindingContext)
    {
        ValueProviderResult valueResult = bindingContext.ValueProvider
            .GetValue(bindingContext.ModelName);
        ModelState modelState = new ModelState { Value = valueResult };
        object actualValue = null;
        try
        {
            actualValue = Convert.ToDecimal(valueResult.AttemptedValue,
                CultureInfo.CurrentCulture);
        }
        catch (FormatException e)
        {
            modelState.Errors.Add(e);
        }

        bindingContext.ModelState.Add(bindingContext.ModelName, modelState);
        return actualValue;
    }

模型绑定器中的错误Input string was not in a correct format

 Convert.ToDecimal("$200,150.90",CultureInfo.CurrentCulture)

1 个答案:

答案 0 :(得分:0)

如果格式为货币,则添加额外的十进制转换

感谢Convert currency string to decimal?

 string currencyDisplayFormat=(bindingContext.ModelMetadata).DisplayFormatString;
 if (!string.IsNullOrEmpty(currencyDisplayFormat) 
                           && currencyDisplayFormat == "{0:c}")
 {
    actualValue = Decimal.Parse(valueResult.AttemptedValue,
                  NumberStyles.AllowCurrencySymbol | NumberStyles.Number, 
                  CultureInfo.CurrentCulture);

 }
 else
 {
        actualValue = Convert.ToDecimal(valueResult.AttemptedValue,
                        CultureInfo.CurrentCulture);
 }