我如何继续这样做?我不喜欢按每个按钮的想法。我真的想要了解所有这一切。我得到了绑定的概念我只是不知道该怎么做。
from tkinter import *
class Calc():
def __init__(self):
self.total = 0
self.current = ""
self.new_num = True
self.op_pending = False
self.op = ""
self.eq_flag = False
def num_press(self, num):
temp = text_box.get()
self.eq_flag = False
temp2 = str(num)
if self.new_num == True:
self.current = temp2
self.new_num = False
else:
if temp2 == '.':
if temp2 in temp:
return
self.current = temp + temp2
text_box.delete(0, END)
text_box.insert(0, self.current)
def calc_total(self):
if self.op_pending == True:
self.do_sum()
self.op_pending = False
def do_sum(self):
self.current = float(self.current)
if self.op == "add":
self.total += self.current
if self.op == "minus":
self.total -= self.current
if self.op == "times":
self.total *= self.current
if self.op == "divide":
self.total /= self.current
text_box.delete(0, END)
text_box.insert(0, self.total)
self.new_num = True
def operation(self, op):
if self.op_pending == True:
self.do_sum()
self.op = op
else:
self.op_pending = True
if self.eq_flag == False:
self.total = float(text_box.get())
else:
self.total = self.current
self.new_num = True
self.op = op
self.eq_flag = False
def cancel(self):
text_box.delete(0, END)
text_box.insert(0, "0")
self.new_num = True
def all_cancel(self):
self.cancel()
self.total = 0
def sign(self):
self.current = -(float(text_box.get()))
text_box.delete(0, END)
text_box.insert(0, self.current)
class My_Btn(Button):
def btn_cmd(self, num):
self["command"] = lambda: sum1.num_press(num)
sum1 = Calc()
root = Tk()
calc = Frame(root)
calc.grid()
root.title("Calculator")
text_box = Entry(calc, justify=RIGHT)
text_box.grid(row = 0, column = 0, columnspan = 4, pady = 5, padx=5)
text_box.insert(0, "0")
#Buttons
numbers = "789456123"
i = 0
bttn = []
for j in range(2,5):
for k in range(3):
bttn.append(My_Btn(calc, text = numbers[i]))
bttn[i].grid(row = j, column = k, pady = 5, padx=5)
bttn[i].btn_cmd(numbers[i])
i += 1
clear = Button(calc, text = "C", width =1, height =1)
clear["command"] = sum1.cancel
clear.grid(row = 1, column = 0, pady = 5, padx=5)
all_clear = Button(calc, text = "AC", width =1, height =1)
all_clear["command"] = sum1.all_cancel
all_clear.grid(row = 1, column = 1, pady = 5, padx=5)
bttn_div = Button(calc, text = chr(247))
bttn_div["command"] = lambda: sum1.operation("divide")
bttn_div.grid(row = 1, column = 2, pady = 5, padx=5)
bttn_mult = Button(calc, text = "x", width =1, height =1)
bttn_mult["command"] = lambda: sum1.operation("times")
bttn_mult.grid(row = 1, column = 3, pady = 5, padx=5)
minus = Button(calc, text = "-", width =1, height =1)
minus["command"] = lambda: sum1.operation("minus")
minus.grid(row = 2, column = 3, pady = 5, padx=5)
add = Button(calc, text = "+", width =1, height =1)
add["command"] = lambda: sum1.operation("add")
add.grid(row = 3, column = 3, pady = 5, padx=5)
neg= Button(calc, text = "+/-", width =1, height =1)
neg["command"] = sum1.sign
neg.grid(row = 4, column = 3, pady = 5, padx=5)
equals = Button(calc, text = "=", width =1, height =1)
equals["command"] = sum1.calc_total
equals.grid(row = 5, column = 3, pady = 5, padx=5)
point = Button(calc, text = ".", width =1, height =1)
point["command"] = lambda: sum1.num_press(".")
point.grid(row = 5, column = 2, pady = 5, padx=5)
bttn_0 = Button(calc, text = "0", width =7, height =1)
bttn_0["command"] = lambda: sum1.num_press(0)
bttn_0.grid(row=5, column = 0, columnspan = 2, pady = 5, padx=5)
答案 0 :(得分:2)
我会使用Entry小部件,而不是绑定每个键。人们会犯错误。他们想要按下退格键,或者使用箭头键或鼠标将光标放在某处并编辑他们输入的内容。你不想重新发明这一切。如果你给他们一个Entry小部件,你可以免费获得所有的编辑功能,并且可以在按Enter键时解析结果。
entry.bind('<Enter>', parse)
答案 1 :(得分:1)
我认为正确的方式是unutbu建议的方式,使用Entry。 (你可以使用ttk主题,如果你想使它看起来不像普通的条目,你可以使用焦点技巧使其工作,即使用户没有点击它。)
但是,如果你希望以自己的方式做事,你可以。您的key
函数可以调度到执行实际工作的函数(append_digit
表示数字,backspace
表示退格/删除)。然后,如果你想要按钮做同样的事情,你可以添加它们,回调分派到相同的功能。例如:
from functools import partial
from Tkinter import *
root = Tk()
def key(event):
print "pressed", repr(event.char)
if event.char.isdigit():
append_digit(event.char)
elif event.char in ('\x08', '\x7f'):
backspace()
def callback(event):
frame.focus_set()
print "clicked at", event.x, event.y
frame = Frame(root, width=100, height=100)
frame.bind("<Key>", key)
frame.bind("<Button-1>", callback)
frame.pack()
current = IntVar(0)
label = Label(frame, textvariable=current)
label.pack()
def button_callback(i):
print "clicked button {}".format(i)
append_digit(i)
def append_digit(digit):
current.set(current.get() * 10 + int(digit))
def backspace():
current.set(current.get() // 10)
for i in '1234567890':
Button(frame, text=i, command=partial(button_callback, i)).pack()
Button(frame, text='C', command=backspace).pack()
frame.focus_set()
root.mainloop()
显然你可以添加更多按键和/或按钮 - 例如,“+”键和标有“+”的按钮都会触发添加功能,或者标有“AC”的按钮会触发current.set(0)
功能,或者你想要什么。并且大概你可以设计一个比长按钮更好的用户界面。这只是为了向您展示这个想法。