c ++ 2d数组到函数

时间:2013-04-09 19:22:59

标签: c++ arrays function

该代码应该使用2d数组来获取3只猴子在一周内食用的食物并找到平均值,一天食用最低,一天食用量最高。最少的功能应该输出一只猴子在一天内吃掉的最低值,包括猴子数量,吃掉的磅数和日数。与最高功能相同。但它没有正确计算,我不知道我是否做错了。当我运行它打印出“吃掉的最低量是第1天的猴子1是1”然后打印出2,3,4等我尝试将cout放在循环外但是然后计数未初始化

#include <iomanip>
#include <iostream>  
using namespace std;

//Global Constants
const int NUM_MONKEYS = 3; // 3 rows
const int DAYS = 7; // 7 columns

//Prototypes
void poundsEaten(double[][DAYS],int, int);
void averageEaten(double [][DAYS], int, int);
void least(double [][DAYS], int, int);
void most(double [][DAYS], int, int);

int main()
{
//const int NUM_MONKEYS = 3;
//const int DAYS = 7;
double foodEaten[NUM_MONKEYS][DAYS]; //Array with 3 rows, 7 columns 

poundsEaten(foodEaten, NUM_MONKEYS, DAYS);
averageEaten(foodEaten, NUM_MONKEYS, DAYS);
least(foodEaten, NUM_MONKEYS, DAYS);
most(foodEaten, NUM_MONKEYS, DAYS);

system("pause");
return 0;
}

void poundsEaten(double monkey[][DAYS], int rows, int cols)
{
for(int index = 0; index < rows; index++)
{
    for(int count = 0; count < cols; count++)
    {
        cout << "Pounds of food eaten on day " << (count + 1);
        cout << " by monkey " << (index + 1) << ": ";
        cin >> monkey[index][count];

    }
} 
}

void averageEaten(double monkey[][DAYS], int rows, int cols)
{
for(int count = 0; count < cols; count++)
{
    double total = 0;
    double average;
    for(int index = 0; index < rows; index++)
    {
        total += monkey[index][count]; 

        average = total/rows;
    }
    cout << "The average food eaten on day " << (count + 1)
             <<" is " << average << endl;

}
}

void least(double monkey[][DAYS], int rows, int cols)
{
double lowest = monkey[NUM_MONKEYS][DAYS];
for(int index = 0; index < rows; index++)
{
    for(int count = 0; count < cols; count++)
    {
        if(monkey[index][count] > lowest)
            lowest = monkey[index][count];

        cout << "The lowest amount of food eaten was monkey number 
                       << " " << (index + 1)
               << " On day " << (count + 1) << " was " << lowest;
    }

}


}

void most(double monkey[][DAYS], int rows, int cols)
{
double highest = monkey[NUM_MONKEYS][DAYS];
for(int index = 0; index < rows; index++)
{
    for(int count = 0; count < cols; count++)
    {
        if(monkey[index][count] > highest)
            highest = monkey[index][count];

    cout << "The highest amount of food eaten was monkey number"
         << (index + 1) << " on day " << (count + 1)  << " was "  
                  << highest;
    }
}


}

1 个答案:

答案 0 :(得分:1)

来自least功能:

if(monkey[index][count] > lowest)
    lowest = monkey[index][count];

在比较中,我确定您的意思是<,而不是>

您还应该保存索引并在循环后打印,这适用于leastmost