Question

我知道ROT13有无数种方法，Python甚至还有内置函数，但我真的想了解如何修改我编写的代码。当我在我的编辑器中测试它（保持空白区域，标点符号和大小写）但它在我的网页中不起作用时，它工作正常。我被告知我只是打印字符而不是将它们复制到结果字符串中。我玩了好几个小时但还没弄明白如何操纵它以包含一个返回声明。

对不起，如果这是一个愚蠢的问题 - 我是新手:)任何帮助都非常感激。

dictionary = {'a':'n', 'b':'o', 'c':'p',
             'd':'q', 'e':'r', 'f':'s',
             'g':'t','h':'u','i':'v',
             'j':'w', 'k':'x','l':'y',
             'm':'z','n':'a','o':'b',
             'p':'c','q':'d','r':'e',
             's':'f','t':'g','u':'h',
             'v':'i', 'w':'j','x':'k',
             'y':'l','z':'m'}

def rot(xy):

    for c in xy:

        if c.islower():
            print dictionary.get(c),

        if c.isupper():
            c = c.lower()
            result = dictionary.get(c)
            print result.capitalize(),

        if c not in dictionary:
            print c,

    return rot

Answer 1

正如您自己写的那样，您正在打印结果。打印到标准输出在Web应用程序中不起作用，因为它们通常使用协议（unix套接字等）将数据传送回Web服务器进程（或者使用基于Python的Web服务器，如Twisted，在这种情况下标准输出将转到您启动该过程的控制台。）

因此，在您编写时，您需要修改该函数以便返回值而不是打印它。有无数种方法可以做到这一点，最简单的方法是用StringIO对象替换标准输出：

from StringIO import StringIO

def rot(xy):
    rot = StringIO()
    for c in xy:

        if c.islower():
            print >>rot, dictionary.get(c),

        if c.isupper():
            c = c.lower()
            result = dictionary.get(c)
            print >>rot, result.capitalize(),

        if c not in dictionary:
            print >>rot, c,

    return rot.getvalue()

更基本的方法是将输出存储在列表中：

def rot(xy):
    rot = []
    for c in xy:

        if c.islower():
            rot.append(dictionary.get(c))

        if c.isupper():
            c = c.lower()
            result = dictionary.get(c)
            rot.append(result.capitalize())

        if c not in dictionary:
            rot.append(c)

    return ''.join(rot)

Answer 2

你只是打印出价值，你不会腐烂。事实上，你正在返回函数本身，这根本不对。

Answer 3

dictionary = {'a':'n', 'b':'o', 'c':'p',
             'd':'q', 'e':'r', 'f':'s',
             'g':'t','h':'u','i':'v',
             'j':'w', 'k':'x','l':'y',
             'm':'z','n':'a','o':'b',
             'p':'c','q':'d','r':'e',
             's':'f','t':'g','u':'h',
             'v':'i', 'w':'j','x':'k',
             'y':'l','z':'m'}

def rot(xy):
    rot13 = ''
    for c in xy:
        if c.islower():
            rot13 += dictionary.get(c)
        if c.isupper():
            c = c.lower()
            rot13 += dictionary.get(c).capitalize()
        if c not in dictionary:
            rot13 += c
    print "ROTTED: ", rot13  
    return rot13

Answer 4

#!/usr/bin/env python
import string

# Create alpha using 'string.ascii_uppercase' and 'string.ascii_lowercase' methods.
# Create rotated 13 using list/array positioning
# Create translation table using string.maketrans()
# Use translation table using string.translate()

# Get the alpha
alphaUpper=string.ascii_uppercase
rotatedUpper=alphaUpper[-13:] + alphaUpper[:-13]

alphaLower=string.ascii_lowercase
rotatedLower=alphaLower[-13:] + alphaLower[:-13]

combinedOriginal=alphaLower + alphaUpper
combinedRotated=rotatedLower + rotatedUpper

print combinedOriginal
print combinedRotated

translation_table = string.maketrans( combinedOriginal, combinedRotated )

message="This is the original message."

print message.translate(translation_table)
print message.translate(translation_table).translate(translation_table)

运行脚本将产生：

$ ./rot.py 
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
nopqrstuvwxyzabcdefghijklmNOPQRSTUVWXYZABCDEFGHIJKLM
Guvf vf gur bevtvany zrffntr.
This is the original message.

Answer 5

alphabets = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
c_alphabets = []
for i in alphabets:
   c_alphabets.append(i.capitalize())
def rot13(s):
    out_string=''
    for i in s:
        if i in alphabets:
            j = alphabets[(alphabets.index(i) + 13) % 26]
            out_string += j
        elif i in c_alphabets:
            j = c_alphabets[(c_alphabets.index(i) + 13) % 26]
            out_string += j
        else:
            out_string += i
    return out_string

如何重新使用此ROT13功能

5 个答案: