Question

我有一个字符串可以说C1 AND C2 OR C3 (~!@#$%) AND C4 OR C5 并说我的输入是C3 然后我想使用正则表达式删除C3和下一个运算符AND|OR之间的垃圾/数据。

所以对于上面的字符串我希望输出为C1 AND C2 OR C3 AND C4 OR C5

Answer 1

试试这个：

var str = 'C1 AND C2 OR C3 (~!@#$%) AND C4 OR C5'
var input = 'C3'
console.log(str.replace(new RegExp("(" + input + " ).*?(AND|OR)"), "$1$2"))

Answer 2

function purgeJunk(variable, expression) {
    return expression.replace(purgeJunk.regexp, function(match, digits, operator) {
        if (digits != variable) return match;
        return "C" + digits + " " + operator;
    });
};

function purgeAllJunk(expression) {
    return expression.replace(purgeJunk.regexp, function(match, digits, operator) {
        return "C" + digits + " " + operator;
    });
};

purgeJunk.regexp = /C(\d+) .*?(AND|OR)/g;

// delete junk after C2
purgeJunk(2, "C1 AND C2 OR C3 (~!@#$%) AND C4 OR C5") 
    == "C1 AND C2 OR C3 (~!@#$%) AND C4 OR C5"

// delete junk after C3
purgeJunk(3, "C1 AND C2 OR C3 (~!@#$%) AND C4 OR C5") 
    == "C1 AND C2 OR C3 AND C4 OR C5"

// delete all junk
purgeAllJunk("C1 # AND C2 OR C3 ~!@#$% ()()()() ### AND C4 more garbage OR C5")
    == "C1 AND C2 OR C3 AND C4 OR C5"

字符串使用正则表达式进行操作

2 个答案: