Question

我有如下所述的设置

> create table earnings(earning_id number,
>                      col1 number,
>                      col2 number);
>
>create table trans(trans_id number,
>                   trans_attr1 number,
>                   trans_attr2 number);
>
>create or replace type trans_obj as object
>                   (trans_id number,
>                    trans_attr1 number,
>                    trans_attr2 number);
>
>create or replace type trans_coll as table of trans_obj;
>
>create or replace type earning_obj as object 
> (
>  earning_id number,
>  col1 number,
>  col2 number
>  );
>
>create or replace type earnings_coll as table of earnings_obj;
>
>/

我有一个表函数如下

函数计算（trans_t trans_coll）       return earnings_coll pipelined;

我想做类似下面的事情

>>  function get_results(trans_t trans_coll)
>>  return earnings_coll pipelined 
>>   as
>>      l_earning_rec earnings_obj;
>>    
>>   begin
>>     
>>     for earning in (select * from table(calculate(trans_t)))
>>      loop
>>         l_earning_rec.extend();
>>         // copy value from earning to l_earning_rec without having to copy each
>>         // attribute individually
>>         
>>         pipe row(l_earning_rec);
>>      end loop;
>>    
>>    return;
>>   end get_results;

如果有办法，请告诉我。

此外，如果get_results是一个只会将记录插入收入表的程序，我该怎么办呢

insert into earnings 
   values (select * from table(calculate(trans_t)))

由于

Answer 1

如果有帮助，你可以将功能更改为：

for earning in (select earnings_obj(earning_id, col1, col2) a
                 from table(calculate(trans_t)))
loop
   pipe row(earning.a);
end loop;

至于你的插入，你只需将其写为：

insert into earnings 
select * from table(calculate(trans_t));

Answer 2

我一直在使用“10g PL / SQL编程指南”学习PL / SQL，我不认为有这样的事情。

如何使用表函数中的记录将记录插入表中

2 个答案: