我需要在此页面中输出jpeg图像。查看下面的代码,我有一个表单设置,向用户显示数据。在此表单或表单下方,我需要输出图像。代码作为PHP文件运行,因此普通的HTML标记不起作用。有什么想法吗?
<!DOCTYPE html>
<?php
session_start();
?>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1" />
<meta name="apple-mobile-web-app-capable" content="yes" />
<meta name="apple-mobile-web-app-status-bar-style" content="black" />
<title>
</title>
<link rel="stylesheet" href="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.css" />
<link rel="stylesheet" href="my.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js">
</script>
<script src="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.js">
</script>
<script src="my.js">
</script>
<!-- User-generated css -->
<style>
</style>
<!-- User-generated js -->
<script>
try {
$(function() {
});
} catch (error) {
console.error("Your javascript has an error: " + error);
}
</script>
</head>
<body>
<!-- Home -->
<div data-role="page" id="page1">
<div data-theme="a" data-role="header">
<a data-role="button" data-theme="d" href="login.html" data-icon="arrow-l" data-iconpos="left" class="ui-btn-left">
Back
</a>
<a data-role="button" href="index.html" data-icon="home" data-iconpos="right" data-theme="d"class="ui-btn-right">
Home
</a>
<h3>
Book Car
</h3>
</div>
<div data-role="content">
<h3>
Select the car to rent from the availability:
</h3>
<br />
<?php
{
mysql_connect("localhost" , "" , "") or die (mysql_error());
mysql_select_db("") or die(mysql_error());
$pid=intval($_SESSION["User_id"]);
$query = "SELECT `car`, `details`, `price` FROM `Car`";
//executes query on the database
$result = mysql_query ($query) or die ("didn't query");
//this selects the results as rows
$num = mysql_num_rows ($result);
while($row=mysql_fetch_assoc($result))
{
$_SESSION['car'] = $row['car'];
$_SESSION['details'] = $row['details'];
$_SESSION['price'] = $row['price'];
}
}
?>
<!DOCTYPE html>
<html>
<body>
<form action="demo_form.asp">
Car: <input type="text" name="country" value="<?php echo $_SESSION['car']; ?>" readonly><br>
Details: <input type="text" name="country" value="<?php echo $_SESSION['details']; ?>" readonly><br>
Price: <input type="text" name="country" value="<?php echo $_SESSION['price']; ?>" readonly><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
答案 0 :(得分:0)
在你的php脚本中,在任何输出之前添加 ,这样php就会被读作图像:
header("Content-Type: image/jpg"); //or image/gif or image/png ...
然后您可以在表单中添加:
<img src='my_php_script.php?image=1' />
您可以通过将参数传递给php脚本来识别图像。
答案 1 :(得分:0)
你有两次:<!DOCTYPE html>
。那是错的。此外:标准HTML在您的表单下方<img src="yourimg.jpg" alt="this img" />
正常工作,并且已完成